GPT 6 Astra Ultra attempt on Math-6258
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Contents
Erdős Problem 1204 --- GPT 6 Astra Ultra partial attempt
FORMAL RESTATEMENT
A $k$-tuple of integers $0\leq a_1<\cdots<a_k$ is admissible when its residues omit some class modulo each prime. Minimise, over these tuples, the quantities \[A(k)=\min a_k,\qquad B(k)=\min\frac1k\sum_{i=1}^k a_i.\] Estimate both functions; in particular, is $A(k)\sim k\log k$? The accompanying remarks also ask about the growth of the greedy admissible sequence beginning at $0$.CONTEXT AND SCOPE
This replaces the earlier statement-only record with an elementary mathematical attempt. The arguments below establish only their stated partial results; no novelty or full solution is claimed.The source's description of the greedy recurrence has indexing slips; no recurrence with those slips is reproduced.
ATTACK PLAN AND WORK
Only primes at most $k$ need be checked for admissibility: a $k$-element tuple cannot occupy all residue classes of a larger prime. Translation preserves admissibility, so minimizing either quantity permits normalization $a_1=0$. For $k\ge2$, omission of a residue modulo two then forces all elements to be even. Thus \[A(k)\ge2(k-1),\qquad B(k)\ge k-1.\tag{1}\]An explicit upper construction is also immediate. Put $Q_k=\prod_{p\le k}p$ and take $a_i=(i-1)Q_k$. For primes at most $k$ this tuple occupies only residue zero; for larger primes it occupies fewer than all residues. Hence \[A(k)\le(k-1)Q_k,\qquad B(k)\le\tfrac12(k-1)Q_k.\tag{2}\] These upper bounds are far from the conjectured scale.
The finite-prime reduction gives an exact small-$k$ search for $A(k)$: enumerate increasing even tuples starting at zero by increasing final element, checking residues only for primes at most $k$. The first success is minimal, since every smaller normalized endpoint was exhaustively tested. The local check performs this search for $2\le k\le6$; it does not claim to minimize $B(k)$ by simply using the tuple that minimizes its last element.