Econ-84 · economics · computer science · Computational economics

Econ-84 · CS-858

Exact stationary equilibria with three or more discounted players

LLM status Open unverified

C73 — Stochastic and Dynamic Games - Evolutionary Games - Repeated Games Economics catalogue openaigpt 6 astra ultra 15% cataloguednot recordedOpen

Statement

GT-035 | Stochastic games and computational complexity

P | Corrected unresolved multi-player complexity target; two-player classification known

Definitions and mathematical statement

A discounted perfect-information stochastic game has finite states $S$, a controlling player $c(s)\in\{1,\ldots,n\}$ at each state, finite actions $A(s)$ for its controller, rational payoffs $r_i(s,a)$ and transition probabilities $P(s'\mid s,a)$, and rational $\gamma\in(0,1)$. All data are explicitly listed in binary. A stationary profile is $x(\cdot\mid s)\in\Delta(A(s))$. Its normalized discounted payoff from $s$ is \[ V_i^x(s)=(1-\gamma)\mathbb E_{s,x}\sum_{t\geq0}\gamma^t r_i(s_t,a_t). \] The exact search relation asks for $x$ that is a Nash equilibrium from every initial state against arbitrary behavioral unilateral deviations. Equivalently, with $r_i^x(s)=\sum_a x(a\mid s)r_i(s,a)$ and $P^x(s'\mid s)=\sum_a x(a\mid s)P(s'\mid s,a)$, it asks for real $x,V$ satisfying the simplex constraints and \begin{align*} V_i(s)&=(1-\gamma)r_i^x(s)+\gamma\sum_{s'}P^x(s'\mid s)V_i(s'),\\ (1-\gamma)r_{c(s)}(s,a)+\gamma\sum_{s'}P(s'\mid s,a)V_{c(s)}(s')&\leq V_{c(s)}(s) \quad(s\in S,\ a\in A(s)). \end{align*} Classify this exact search problem for $n\geq3$, with fixed-$n$ subcases distinguished; in particular, determine whether the source's FIXP upper bound can be matched by FIXP-hardness under the corresponding exact fixed-point reductions.

Short English statement

What is the exact complexity of stationary equilibrium computation once the discounted game has at least three players?

Variants and scope boundaries

Exact solutions can be irrational, so an ordinary finite rational-output requirement is not adequate. FIXP treats exact real fixed points of rational algebraic circuits as solutions; bit approximation and approximate equilibrium are different search relations. Every-state optimality is part of the source convention. The number of players, discount encoding, and action counts cannot be hidden when stating a reduction.

Source relationship and status

[S1] already proves PPAD-completeness for the two-player case (Theorem 1). It leaves the precise complexity for three or more players open, with irrational examples and a four-player SqrtSum-hardness result (Theorem 3). Section 6 identifies possible FIXP-hardness as a remaining question. The original unrestricted "complexity unresolved" wording is therefore corrected.

References

[S1] Kristoffer Arnsfelt Hansen and Xinhao Nie, On the Complexity of Stationary Nash Equilibria in Discounted Perfect Information Stochastic Games, arXiv:2510.11550v1 (2025). Locators: abstract; Section 2.1 (game and equilibrium convention); Theorems 1 and 3; Section 6 (remaining complexity and FIXP-hardness questions). https://arxiv.org/html/2510.11550v1

Common conventions: Source mathematical conventions

Finite games. For a finite set $A$, $\Delta(A)$ is its probability simplex. Players choose independent mixed strategies in Nash equilibrium; correlation is allowed only when explicitly part of the solution concept. In a game with payoff functions $u_i$ and strategy profile $x$, an additive $\varepsilon$ Nash equilibrium satisfies \[ u_i(x)\geq u_i(x_i',x_{-i})-\varepsilon \quad\text{for every player $i$ and every admissible deviation $x_i'$}. \] For numerical approximation, payoffs are normalized as locally specified. An $\varepsilon$ payoff residual is distinct from distance at most $\varepsilon$ to the set of exact equilibria. Point convergence, convergence of empirical play, and convergence in distance to an equilibrium set are also distinct.

Computational representations. Unless stated otherwise, a complexity question takes rational data with binary encoding; polynomial time is measured in total bit length. A fixed-accuracy polynomial algorithm is not necessarily polynomial in $1/\varepsilon$, and neither is necessarily polynomial in $\log(1/\varepsilon)$. Succinct games and value, demand, or sampling oracles must declare their interfaces. Exact real solutions require an explicit representation; an unspecified list of arbitrary real numbers is not a finite computational output. A claimed algorithmic barrier is meaningful only for its specified model and reductions.

Dynamic games. Histories, information, observation, and allowable randomization are part of the model. A stationary strategy depends only on the current state; a positional strategy in a deterministic graph game chooses one action at each controlled vertex. Nash equilibrium at an initial state and equilibrium after every history are different requirements. An expectation of a pathwise $\liminf$ payoff, a $\liminf$ of expected averages, a limiting expected average, and a uniform finite-horizon equilibrium are different criteria. None is silently substituted for another.

Allocation and mechanisms. A complete allocation assigns every item exactly once unless otherwise stated. Zero-valued goods, negative values, capacity constraints, feasibility, lotteries, and copies of goods affect fairness definitions and are specified locally. Dominant-strategy incentive compatibility, Bayesian incentive compatibility, universal truthfulness, and truthfulness in expectation impose different inequalities. Whenever an objective ratio has zero denominator, its convention is stated or those instances are excluded.

Infinite-dimensional models. Expectations, integrals, stochastic equations, and optimization objectives require their local regularity, integrability, filtrations, and admissible domains. A backward--forward mean-field system is a boundary-value problem; it is not an initial-value semiflow without an additional construction. Long-time, large-population, and vanishing-noise limits require an order of limits and a convergence topology. If a minimum need not be attained, the objective is its infimum or supremum and the approximation requirement is stated separately.

Statement licence: CC-BY-4.0 · Source file

Contributions 1

Econ-84-A1 · Exploration · LLM-generated · gpt 6 astra ultra ·

GPT 6 Astra Ultra attempt on Econ-84

Exact stationary equilibria with three or more discounted players: Exact rational equilibria in triangular transition structures

The main problem asks for the exact complexity of stationary equilibrium computation with at least three players in discounted perfect-information stochastic games. The values are normalized by \[ V_i^x(s)=(1-\gamma)\mathbb E_{s,x}\sum_{t\geq0}\gamma^t r_i(s_t,a_t), \qquad 0<\gamma<1. \] An exact equilibrium must be optimal against behavioral deviations from every state. Here is a subclass in which the full exact search problem has a pure rational solution obtainable in polynomial time. It isolates genuine multi-state recurrence as necessary for any hardness construction outside this subclass.

Theorem (Self-loops and strictly downstream transitions): Suppose the states admit an ordering $1,\ldots,d$ such that, for every state $s$ and every available action $a$, $P(t\mid s,a)=0$ whenever $t>s$. Thus an action can stay at $s$ or move to a smaller-indexed state. Assume finite action sets and explicitly encoded rational rewards, probabilities, and discount factor. For any number of players, a pure stationary equilibrium from every state can be computed in polynomial bit time. Its values are rational of polynomial encoding length.
Proof: Process states in increasing order. Suppose all values $V_i(t)$ for $t<s$ have been determined. For every action at $s$ define \[ Q_i(s,a)=\frac{(1-\gamma)r_i(s,a)+\gamma\sum_{t<s}P(t\mid s,a)V_i(t)} {1-\gamma P(s\mid s,a)}. \] The denominator is positive, at least $1-\gamma$. Choose $a_s$ maximizing $Q_{c(s)}(s,a)$ for the controller $c(s)$, and set $V_i(s)=Q_i(s,a_s)$ for all $i$. This gives the evaluation identities for the pure profile $f(s)=a_s$.

For each alternative action $a$ at $s$, maximality implies \[ (1-\gamma)r_{c(s)}(s,a)+\gamma\sum_{t<s}P(t\mid s,a)V_{c(s)}(t) \leq(1-\gamma P(s\mid s,a))V_{c(s)}(s). \] Moving the self-loop term to the left yields the controller's one-step Bellman inequality. For any other player, the selected action gives its evaluation equality.

Fix player $i$ and any behavioral unilateral deviation. At every visited state controlled by $i$, the Bellman inequality remains true after taking the deviating distribution over actions. At states controlled by others it holds as equality. Iterating conditional expectations for $h$ steps yields \[ V_i(s)\geq(1-\gamma)\mathbb E\sum_{t=0}^{h-1}\gamma^t r_i(s_t,a_t) +\gamma^h\mathbb E[V_i(s_h)]. \] Rewards and the finitely many values are bounded, so the last term tends to zero. This proves the full behavioral Nash inequalities at every initial state.

For bit complexity, every selected pure policy on a prefix has a rational linear evaluation system with a triangular coefficient matrix $I-\gamma P^f$. Clearing denominators in this explicitly encoded system and applying the determinant formula bounds numerator and denominator lengths by a polynomial in the input length and number of states. All candidate $Q_i(s,a)$ are obtained from polynomially many such rational values by sums, products, and a division by a nonzero rational. Their lengths are therefore polynomial as well. Exact rational comparisons and the stated arithmetic operations take polynomial time, and there are polynomially many candidates. ∎

Proposition (A pure-policy verification certificate without triangularity): For an arbitrary rational discounted perfect-information game, a specified pure stationary profile can be checked for every-state equilibrium in polynomial bit time.
Proof: Solve $(I-\gamma P^f)V_i=(1-\gamma)r_i^f$ for every player. The matrix is invertible because its inverse is $\sum_{t\geq0}\gamma^t(P^f)^t$. Rational linear algebra has polynomial bit complexity for an explicitly encoded nonsingular system. Check every controller-action Bellman inequality using the computed values. Necessity follows by making a one-step deviation and then following $f$. Sufficiency follows by the same finite-horizon telescoping argument used in the theorem. Hence the certificate is exact against arbitrary behavioral deviations, not merely stationary deviations. ∎
Source relationship and remaining gap.
Hansen and Nie [source], Section 6, ask about FIXP-hardness for three or more players; their two-player classification does not answer that question. The triangular-state calculation is a direct restricted derivation. An unrestricted game may lack a pure equilibrium and may require irrational probabilities. The verification proposition therefore gives no general rational certificate or PPAD upper bound. The exact complexity of the unrestricted relation remains unresolved by these results.

References

  • [source] K. A. Hansen and X. Nie. On the Complexity of Stationary Nash Equilibria in Discounted Perfect Information Stochastic Games, version 1, 2025. https://arxiv.org/html/2510.11550v1.

Completion Estimate

15%

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