Math-6211 · mathematics · Mathematics

Math-6211

Erdős Problem #1157

Status Open · erdosproblems.comLLM status Open unverified

Erdős problems openaigpt 6 astra ultra 8% cataloguedOpenOpen

Statement

Fix parameters $r,k,s\geq2$, and let $\mathcal F_{r,k,s}$ consist of all $r$-uniform hypergraphs on $k$ vertices with $s$ edges. Determine \[ \operatorname{ex}_r(n,\mathcal F_{r,k,s}), \] the largest edge count of an $n$-vertex $r$-uniform hypergraph containing no member of that family as a subhypergraph.

Restatement from Math-6211-A1 r1, with the source manuscript’s qualifications.

Original problem on erdosproblems.com

Statement licence: CC-BY-4.0 · Source file

Contributions 1

Math-6211-A1 · No claim recorded · LLM-generated · gpt 6 astra ultra ·

GPT 6 Astra Ultra attempt on Math-6211

Erdős Problem 1157 --- GPT 6 Astra Ultra partial attempt

FORMAL RESTATEMENT

Fix parameters $r,k,s\geq2$, and let $\mathcal F_{r,k,s}$ consist of all $r$-uniform hypergraphs on $k$ vertices with $s$ edges. Determine \[ \operatorname{ex}_r(n,\mathcal F_{r,k,s}), \] the largest edge count of an $n$-vertex $r$-uniform hypergraph containing no member of that family as a subhypergraph.

CONTEXT AND SCOPE

This replaces the earlier statement-only record with an elementary mathematical attempt. The arguments below establish only their stated partial results; no novelty or full solution is claimed.

The indexed official opening says t,k,r>=2 but subsequently uses s for the number of edges. This paraphrase consistently names that edge parameter s; it does not repeat the separate conjectural formula in the remarks, where another uniformity-index typo appears.

ATTACK PLAN AND WORK

Assume $n\ge k\ge r$ and $2\le s\le\binom kr$; outside the feasible range the forbidden family may be empty. Being free of this family is equivalent to every $k$-vertex set containing at most $s-1$ edges. Double counting pairs $(e,U)$ with $e\subseteq U$ and $|U|=k$ gives the exact upper bound \[e(H)\binom{n-r}{k-r}\le(s-1)\binom nk, \qquad e(H)\le\frac{s-1}{\binom kr}\binom nr.\tag{1}\]

An alteration argument gives a complementary, usually much smaller, lower bound. Choose each $r$-set independently with probability $p$. There are $\binom nr p$ expected edges. The expected number of forbidden configurations is at most $\binom nk\binom{\binom kr}{s}p^s$. Delete one edge from each surviving forbidden configuration; this destroys all of them, since deletion cannot create a new one. For $a=(k-r)/(s-1)$ and $p=c n^{-a}$ with a sufficiently small fixed $c>0$, both expectation terms have power $n^{r-a}$, with coefficients proportional to $c$ and $c^s$. Their difference is positive. Hence, when $r-a>0$, \[\operatorname{ex}_r(n,\mathcal F_{r,k,s})\gg n^{r-(k-r)/(s-1)}.\tag{2}\] The constants depend on the fixed parameters. A nonpositive exponent is not being interpreted as a growing lower bound.

VERIFICATION AND REMAINING GAP

Close the exponent and constant gaps between $1$ and $2$ in the nontrivial parameter regimes. These are elementary general bounds, not a determination of the requested extremal function.

SOURCES

https://www.erdosproblems.com/1157

FINAL

UNRESOLVED. The full source problem remains outside the scope of the proved partial results.

COMPLETION ESTIMATE

$8\%$. This is a conservative subjective estimate toward the whole problem, not a probability that the argument is correct or a claim that a fixed fraction of the problem has been solved.

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