GPT 6 Astra Ultra attempt on Econ-175
economicsEconomics cataloguecontributionexplorationClaim: exploration
Reported by the author as unresolved.
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Contents
A radial revenue certificate for two-item DSIC auctions
Problem ID:D44-171. Status: unresolved.Target and contribution
The target allows independent bidders with arbitrary continuously differentiable densities on $[0,1]^2$, dependence between an individual's two values, randomized allocations, nonnegative payments, ex post IR, and DSIC at every report. General optimal-mechanism characterization remains unresolved here. We derive a universal revenue upper certificate from the radial envelope identity and pair it with a feasible lower bound for the uniform example. The certificate can be computed independently of a proposed mechanism and does not require differentiability of that mechanism. The cited recent work [Duality] motivates certified multi-bidder bounds; no theorem from it is used in the proof.Write $v=(v_1,v_2)\in[0,1]^2$ for one bidder's type and $r(v)=\max\{v_1,v_2\}$. For a density $f$ and $v\ne0$ define \[ K_f(v)=\int_{r(v)}^1 t^{-3}f(v/t)\,dt, \qquad g_f(v)=f(v)-K_f(v). \] Define arbitrary values at $v=0$, a Lebesgue-null point. These expressions are measurable and finite away from zero because $f$ is continuous on its compact support.
The radial envelope calculation
For fixed $v$, the function $a(t)=u(tv)$ is convex and Lipschitz on $[0,1]$, hence absolutely continuous and differentiable almost everywhere. The scalar $v\cdot x(tv)$ is a subgradient of $a$ at $t$ and therefore equals $a'(t)$ at every differentiability point in the interior. The fundamental theorem for absolutely continuous functions yields $a(1)-a(0)=\int_0^1v\cdot x(tv)\,dt$. Substituting $a(0)=0$ and the utility definition proves both identities. ∎
A certificate against every feasible mechanism
For bidder $i$ with density $f_i$, define virtual coordinates \[ \psi_{ij}(v_i)=v_{ij}\left(1-\frac{K_{f_i}(v_i)}{f_i(v_i)}\right) \quad\text{when }f_i(v_i)>0, \] and set them to zero elsewhere. Zero-density sets can have positive Lebesgue measure; the next proof handles them rather than assuming strict positivity of the input densities.Explicit uniform-bidder bounds
Suppose all $2n$ coordinates are independent uniform random variables on $[0,1]$. Here $f_i=1$ and direct integration gives \[ K_f(v)=\frac{r(v)^{-2}-1}{2},\qquad \psi_j(v)=\frac{v_j}{2}\left(3-r(v)^{-2}\right). \]For one item, a bidder of value $v$ wins with probability $v^{n-1}$ if $v\ge1/2$, and zero otherwise. The scalar envelope calculation gives expected revenue $n\int_{1/2}^1(2v-1)v^{n-1}\,dv$; this can also be obtained by integrating the threshold payment distribution. To verify the envelope calculation directly, expected utility at value $v$ equals $\int_0^v x(t)dt$, so integrating $vx(v)-\int_0^v x(t)dt$ against a uniform value gives $\int_0^1(2v-1)x(v)dv$. Evaluating the displayed integral gives $(n-1+2^{-n})/(n+1)$. Double it for the lower bound.
For the upper bound compute $q(s)={\mathbb{P}}\{\psi_1(v)>s\}$, for $0\le s\le1$. Conditional on $v_1=z$, this probability is zero when $z\le s$. For $z>s$, the inequality is equivalent to $\max\{z,v_2\}>(3-2s/z)^{-1/2}$. If $s<z<a(s)$, its conditional probability is $1-(3-2s/z)^{-1/2}$; if $z>a(s)$ it is one. The equation separating these cases is $3z^2-2sz-1=0$, whose positive root is $a(s)$. Integrating the two intervals gives exactly $q(s)$ above.
Independence across bidders implies ${\mathbb{P}}\{\max_i\psi_{i1}>s\}=1-(1-q(s))^n$. For a random variable bounded above by one, its positive-part expectation is the integral of this survival probability from zero to one. The two items have the same marginal distribution, so Theorem Theorem (Radial upper certificate) gives the asserted upper integral. For almost every profile every coordinate is positive and every $r(v_i)<1$. Thus $\psi_{ij}<v_{ij}$ for all bidders and items; consequently $\max\{0,\max_i\psi_{ij}\}<\max_i v_{ij}$ almost surely. Expectations preserve strictness for these bounded nonnegative differences. Since ${\mathbb{E}}\max_i v_{ij}=n/(n+1)$, the final assertion follows. ∎
Remaining gap and source grounding
The radial certificate gives an upper bound valid for every admissible mechanism, including densities that vanish on sets, and a usable optimality check if a matching DSIC construction is found. We do not find such a construction for arbitrary densities or even establish equality with the uniform lower bound. Optimizing the envelope path or combining more incentive constraints may tighten the certificate. The source's abstract was checked on 9 October 2026 for its multi-item, multi-bidder DSIC scope; its full technical duality theorem was not used or claimed verified.References
- [Duality] Y. Jiang, D. C. Parkes, and T. Wang, Duality for Optimal Multi-Item, Multi-Bidder Auction Design: Revenue Certificates through Deep Learning, arXiv:2606.10112v1, 2026. Abstract (scope and certified-upper-bound agenda). https://arxiv.org/abs/2606.10112v1.