OpenAI claim summary for Math-2628
mathematicsTop Open Problemscontributionliterature_reportClaim: literature report
Summary of a claim published in openai/math; not a claim by this platform.
The source uses the same planar data, continuous radius, continuously differentiable tilt and alignment equation as the question. It permits every finite partition and every selection of tags, supplies one compact nondegenerate triangular-base cylinder for each interval, and asserts uniform convergence of the sum of perpendicular base areas to the displayed integral as the mesh tends to zero. These are all the requested assertions, so the match is full.
Limitations: The linked openai/math material has not been examined or verified by the platform.
Manuscript
Contents
Triangular-cylinder approximation of aligned radial sweeps
OpenAI's claim
OpenAI presents the following claims relevant to this question, with manuscript numbers following paper order in Sources. In manuscript 1 (family 100; 2026-09-27), the asserted result is that radial segment sweeps have finite triangular-base cylinder realizations whose area converges to the weighted parameter cost, including a tetrahedral cover below the half-area bound.Mathematical statement of the claimed result
Manuscript 1.
Choose a Euclidean plane $P$ with unit normal $e$, independent $a,b\in P$, $J=[\alpha,\beta]$ with $\alpha<\beta$, continuous $R\ge0$, a $C^1$ map $w:J\to P$, $p_0\in P$ and $L>0$. Set \[ \mathcal S=\{p_0+\rho(a+tb)+s(e+w(t)):t\in J,0\le\rho\le R(t),|s|\le L\}, \quad\mathcal A=|\det_P(a,b)|\int_{\alpha}^{\beta}\frac{R(t)^2}{2\sqrt{1+\|w(t)\|^2}}\,dt. \] If $w'(t)=\lambda(t)(a+tb)$ for continuous real $\lambda$, every tagged finite partition gives one covering cylinder per interval, with frozen axis $e+w(c_i)$ and nondegenerate compact triangular perpendicular base, whose total base area tends uniformly to $\mathcal A$ as the mesh tends to zero. Frozen projections of the actual interval sweeps give the same limit. The tetrahedral consequence claims, for each regular tetrahedron $K$ of positive edge length, a finite triangular-base cover with \[ \sum_i|B_i|<\tfrac12 A_{\min}(K),\qquad \sum_i\frac{|B_i|}{|\pi_{u_i^{\perp}}K|}<\tfrac12. \]Outline of the argument
For manuscript 1 (family 100; 2026-09-27), one triangular enclosure is assigned to each interval of a tagged partition. Complementary shortened beams leave a strip covered by horizontal cylinders; exact overlap and strip calculations cancel the first-order cost and leave a strict second-order saving.Formal verification
For manuscript 1 (family 100; 2026-09-27), OpenAI lists Lean statements for this assertion: radial segment sweeps have finite triangular-base cylinder realizations whose area converges to the weighted parameter cost, including a tetrahedral cover below the half-area bound.This coverage does not establish a formal proof of the complete problem as stated here.
The linked family Comparator checks are CylinderCovering.lean, RuledCovering.lean, TriangularCovering.lean.
Their named declarations include OAI.CylinderCovering.fourPaperMain, OAI.RuledApproximation.fullMain, OAI.TriangularCovering.main.
This site has not executed the Lean code. Described statement coverage is not an independent proof check.
Status caveat
The manuscripts were produced by an internal OpenAI model. OpenAI cautions that results without formalization can contain mistakes. This site has not independently checked the proofs; the label records the scope of OpenAI's claim.Sources
- OpenAI, Finite triangular approximation of radial sweeps, 2026-09-27; citation key
OAI:Finite-triangular-approximation-of-radial-sweeps-September-27-2026. PDF (GitHub); PDF (direct); Manuscript page and citation; Latest version; Statement source: thm:radial. - Family 100: Lean scope.
- Comparator CylinderCovering.json.
- Comparator CylinderCovering.lean.
- Comparator RuledCovering.json.
- Comparator RuledCovering.lean.
- Comparator TriangularCovering.json.
- Comparator TriangularCovering.lean.
- OpenAI catalogue entry.