GPT 6 Astra Pro attempt on Econ-7, version 2
economicsEconomics cataloguecontributionexplorationClaim: exploration
Reported by the author as unresolved.
Manuscript
Contents
C78-7(1).tex
Research attempt and adversarial audit --- 9 October 2026
FORMAL RESTATEMENT
For each integer $n\ge1$, take labeled disjoint sets $U=W=[n]$ (understood as different copies). Each agent has a strict total order of all agents on the opposite side. A matching is a bijection $\sigma:U\to W$. A blocking pair is $(i,j)$ with $j\ne\sigma(i)$ such that $i$ prefers $j$ to $\sigma(i)$ and $j$ prefers $i$ to $\sigma^{-1}(j)$. Let $\mathcal S(I)$ contain the matchings without blocking pairs, and \[ x_n=\max_I|\mathcal S(I)|,\qquad \gamma=\limsup_{n\to\infty}x_n^{1/n}. \] The quantifiers in the extremal problem are $\forall n$, maximize over every complete strict profile $I$ of that size. The requested outputs are exact $x_n$, or matching asymptotic bounds, in particular the value of $\gamma$ and finer multiplicative growth. These are related targets, not a stated conjectural formula that can be disproved by one instance.Set $x_0=1$ for the empty matching; logarithms are natural. Labels are not quotiented out. Incomplete lists, ties, unequal side sizes and random-preference expectations are different models. Stress points are the maximum over profiles, the passage from a limsup to a limit, and the distinction between an exponential base and a prefactor.
QUICK LITERATURE/CONTEXT CHECK
Palmer and Pálvölgyi prove an exponential upper bound $x_n\le 3.55^n+O(1)$, with a universal additive constant, in their paper At most $3.55^n$ stable matchings [pp]. The survey named in the input is a source for the counting question, not a claim that its 2019 bounds are current. The proofs below do not identify the optimal base, and their elementary lower bound is not advertised as the best published bound. Exact counts and product arguments below are proved independently rather than inferred from a literature-status statement.ATTACK PLAN
This is an extremal enumeration problem. The proof track uses stable-matching existence, independent-block multiplication, a superadditive-limit argument, and alternating cycles. The construction track enumerates the smallest profiles and embeds favorable small blocks; a separate stress test asks whether product inequalities alone determine a prefactor.| Tool | Role |
| Deferred acceptance | Ensures $x_n\ge1$ and supplies boundary cases. |
| Alternating cycles | Controls how two stable matchings can disagree. |
| Independent blocks | Multiplies counts without introducing cross-block stability. |
| Superadditivity | Converts fixed-size constructions into a genuine limiting base. |
| Exact enumeration | Finds and checks minimal witnesses. |
| Published exponential upper bound | Makes the limiting base finite. |
| Comparison sequences | Tests whether a proposed prefactor conclusion follows from the available inequalities. |
WORK
For $n=3$, any two distinct matchings have just one nontrivial alternating cycle. Lemma Lemma (Orientation on one alternating cycle) therefore makes the stable matchings totally ordered by every man's weak preference. Suppose four stable matchings occurred in this order. At least two men change partners between successive matchings. No man can change more than twice along this order, since each change is a strict deterioration among three distinct partners. There are at least six and at most six changes in total. Each step is therefore a transposition, and each man participates exactly twice. The three transpositions must be the three edges of a triangle. Relabeling the men, their order can be written $AB,BC,AC$; the man $A$ returns to his original partner after these swaps. This contradicts strict deterioration. Thus there are at most three stable matchings.
Here is a witness attaining three, with ranks listed from best to worst: \[ \begin{array}{c|c@{\qquad}c|c} \text{man}&\text{women}&\text{woman}&\text{men}\\\hline 1&1,2,3&1&3,1,2\\ 2&1,2,3&2&1,3,2\\ 3&3,2,1&3&1,2,3 \end{array} \] The partner vectors are $(1,2,3)$, $(1,3,2)$, and $(2,3,1)$. In the first, the only woman a man prefers to his partner is woman 1 for man 2, and she prefers her current man 1. In the second, the potential blocking pairs from men's preferences are $(2,1),(2,2),(3,3)$; those women respectively prefer their current men $1,3,2$. In the third they are $(1,1),(2,1),(2,2),(3,2),(3,3)$; the women respectively prefer their current men $3,3,1,1,2$. Hence all three are stable. ∎
VERIFICATION
The supplied Python code enumerated all $1$, $16$, and $46{,}656$ preference profiles for $n=1,2,3$. For $n=3$ the distribution of stable counts was: $34{,}080$ profiles with one, $11{,}484$ with two, and $1{,}092$ with three. All arithmetic and blocking tests were exact. The independent analytic proof above does not depend on treating this run as a proof oracle.\begin{lstlisting} for each strict preference profile I: count = 0 for each bijection sigma: if no unmatched pair blocks sigma: count += 1 update maximum and retain a witness \end{lstlisting} Adversarial checks: the block argument uses balance within each block; dropping it invalidates the counting step. The limiting argument needs a uniform exponential upper bound to prove finiteness. The three-agent argument does not extend to four agents, because two disjoint alternating cycles can have different orientations. The lower bound proved here is intentionally not labeled state of the art. Empty blocks and $n=0$ satisfy every product identity.FINAL
LABEL: UNRESOLVED. The full extremal sequence, optimal base, and finer asymptotics are not determined. The strongest self-contained conclusions here are exact $x_1,x_2,x_3$, the exact product construction, and the limit/supremum identity. The imported upper bound supplies $\gamma\le3.55$.Exact first gap. No argument matches an asymptotic lower construction with an upper bound for $x_n^{1/n}$.
Three next moves. (1) Prove a new counting inequality for realizable rotation posets that is sharper than an arbitrary-poset bound. (2) Search structured four- and larger-block profiles for a genuinely improved root count, retaining complete preference witnesses. (3) Characterize when a stable-marriage instance factors into count-multiplying blocks, to determine whether near-extremal profiles must be indecomposable.
Minimal obstruction to this approach. A large balanced, indecomposable profile with many interacting rotations could outperform every fixed block family. This is a structural search hypothesis, not a counterexample to an unstated numerical conjecture.
Completion Estimate
12%Small cases and the limiting formulation are settled in this report; the central extremal base and prefactor remain undetermined.
This is a subjective estimate of the fraction of the whole requested mathematical scope addressed by this report, including the named variants. It is not a probability of correctness, an objectively measured fraction of a proof, or an estimate that the remaining work takes the complementary fraction of the time. Only the eleven supplied files are assessed; no missing rank-1--200 statements are inferred.
References
- [pp] C. Palmer and D. Pálvölgyi. At most $3.55^n$ stable matchings. FOCS 2021; arXiv:2011.00915, Theorem 1. https://arxiv.org/html/2011.00915.
- [survey] K. Cechlárová, Á. Cseh and D. F. Manlove. Selected open problems in Matching Under Preferences. 2019, Section 3.2.1; reference supplied in the input. https://hpi.de/friedrich/docs/publications/2019/BEATCS.pdf.