GPT 6 Astra Ultra attempt on Econ-75
economicsEconomics cataloguecontributionexplorationClaim: exploration
Reported by the author as unresolved.
Manuscript
Contents
- Random maturity and filtering in joint control and stopping: Survival filtering, a verification theorem, and a closure obstruction
- Target and scope
- Survival changes the posterior before maturity
- A precise conditional obstacle verification
- Finite-dimensional reduction under uninformative observation
- A specific failure of Gaussian closure
- References
- Completion Estimate
Random maturity and filtering in joint control and stopping: Survival filtering, a verification theorem, and a closure obstruction
Target and scope
The partially observed state satisfies $dX_t=u_t\mu(X_t)dt+\sigma(X_t)dW_t$ and $dO_t=h(X_t)dt+dV_t$, with independent Brownian noises and the regularity in the canonical statement. Maturity has state-dependent intensity $a$, where $0<a_0\le a\le a_1$. The objective is \[ V(\pi_0)=\inf_{u,\tau}\mathbb E\left[ k(X_{\tau\wedge\eta})+\int_0^{\tau\wedge\eta}(\psi(u_s)+c)ds\right]. \] The combined research direction originates in [bgk, Section 5]. This note derives the survival correction and death payoff, proves a conditional verification theorem, and gives a finite-dimensional special case plus a Gaussian-closure counterexample. Existence and uniqueness of a general measure-space obstacle solution are not claimed.Survival changes the posterior before maturity
For a bounded $C^2$ test function $\varphi$ with bounded derivatives, write \[ \mathcal L^u\varphi=u\mu\varphi'+\tfrac12\sigma^2\varphi'',\qquad \pi\varphi=\int\varphi\,d\pi. \]Proposition: Before maturity the posterior obeys the weak filtering equation \[
d(\pi_t\varphi)=\{\pi_t\mathcal L^{u_t}\varphi
-\pi_t(a\varphi)+(\pi_ta)(\pi_t\varphi)\}dt
+\{\pi_t(h\varphi)-(\pi_th)(\pi_t\varphi)\}\,dI_t, \tag{1}
\] where $dI_t=dO_t-(\pi_th)dt$ is the continuous observation innovation before killing. The observed maturity intensity is $r(\pi_t)=\pi_ta$; conditional on maturity at time $t$, the posterior payoff is \[
K^{\rm death}(\pi_{t-})=\frac{\pi_{t-}(ak)}{\pi_{t-}a}. \tag{2}
\]
Proof: Work on a finite deterministic interval. Bounded $h$ makes the observation likelihood exponential a true martingale. Under a reference law in which $O$ is Brownian, let \[
Z_t=\exp\left\{\int_0^t h(X_s)dO_s-\tfrac12\int_0^th(X_s)^2ds\right\},
\quad A_t=\int_0^ta(X_s)ds.
\] On histories without maturity, a control can be represented as a functional of observations and elapsed survival; extend that functional to a process on the reference observation space. Define $\zeta_t\varphi=\mathbb E^{0}[Z_te^{-A_t}\varphi(X_t)\mid\mathcal F_t^O]$. The independent exponential threshold gives the survival weight $e^{-A_t}$. Itô's product rule and conditional expectation of the independent signal noise yield \[
d(\zeta_t\varphi)=\zeta_t(\mathcal L^{u_t}\varphi-a\varphi)dt
+\zeta_t(h\varphi)dO_t.
\] Bounded test functions and coefficients justify conditional projection by localization; bounded likelihood moments on finite intervals remove the localization. Bayes' formula gives $\pi_t\varphi=\zeta_t\varphi/\zeta_t1$ on survival. Itô's quotient rule, with $d\zeta_t1=-\zeta_ta\,dt+\zeta_th\,dO_t$, gives (1) after replacing $dO_t$ by $dI_t+\pi_th\,dt$. The compensator of $\mathbf1\{\eta\le t\}$ in the full filtration is $\int_0^{t\wedge\eta}a(X_s)ds$. Optional projection onto observed histories gives intensity $\pi_sa$. Applying the same argument to a marked payoff $k(X_\eta)$ gives predictable payoff rate $\pi_s(ak)$. Dividing the two rates proves (2). Integrable unbounded $k$ follows by nonnegative truncation. ∎
Replacing $\pi(ak)$ by $(\pi a)(\pi k)$ would ignore selection into maturity and is generally incorrect.A precise conditional obstacle verification
For a cylinder function $F(\pi)=f(\pi\varphi_1,\ldots,\pi\varphi_m)$ with $f\in C^2$, define $b_i^u(\pi)=\pi\mathcal L^u\varphi_i-\pi(a\varphi_i)+(\pi a)(\pi\varphi_i)$, $v_i(\pi)=\pi(h\varphi_i)-(\pi h)(\pi\varphi_i)$, and \[ \mathcal A^uF=\sum_i f_i b_i^u+\tfrac12\sum_{i,j}f_{ij}v_iv_j, \quad K(\pi)=\pi k,\quad H^uF=\mathcal A^uF+\psi(u)+c+\pi(ak)-(\pi a)F. \tag{3} \]Theorem: In addition to the canonical model, suppose $k$ is bounded and continuous, and a bounded nonnegative cylinder function $F$ with bounded derivatives satisfies the following conditions on all reachable posteriors: \[
F\le K,\qquad H^uF\ge0\ \ (u\in U),\qquad
\min\{K-F,\inf_{u\in U}H^uF\}=0. \tag{4}
\] Assume a measurable minimizing selector $u^*(\pi)$ exists on $\{F<K\}$, the corresponding separated control is admissible and admits a solution, and the first hitting time $\tau^*$ of $\{F=K\}$ is a stopping time. Then $F(\pi_0)$ is the value and $(u^*,\tau^*)$ is optimal. A hitting time of infinity is allowed.
Proof: For any control, apply Itô's formula to the alive posterior process up to $t\wedge\tau\wedge\eta$. Give the observed process the terminal value $K^{\rm death}(\pi_{\eta-})$ when maturity occurs; its expectation equals the actual maturity payoff by (2). By (1)--(3), the predictable drift of this value plus accumulated running cost before stopping is exactly $H^uF$. The jump contribution is $\pi(ak)-(\pi a)F$, using (2); the continuous drift is $\mathcal A^uF$. Boundedness and localization give, after taking expectations, a lower bound $F(\pi_0)$ for this process at every bounded stopped horizon. At voluntary stopping replace $F(\pi_\tau)$ by $K(\pi_\tau)\ge F(\pi_\tau)$. Since $P(\eta>t)\le e^{-a_0t}$, bounded alive values vanish in expectation as $t\to\infty$. Running costs are nonnegative, and $\psi$ is bounded on compact $U$, so monotone convergence and $\mathbb E\eta\le1/a_0$ justify the limit. Optional projection identifies $\mathbb E K(\pi_\tau)\mathbf1\{\tau<\eta\}$ with the actual voluntary terminal cost. Hence $F\le J(u,\tau)$ for every admissible pair. For the asserted selector, $H^{u^*}F=0$ until $\tau^*$ by (4), and $F=K$ at voluntary stopping. Every inequality becomes equality; the same limit proves $F=J(u^*,\tau^*)$. ∎
The bounded-$k$ restriction makes this a complete verification statement. For quadratic growth one needs corresponding uniform-integrability and generator-domain estimates; those are not silently supplied by notation.Finite-dimensional reduction under uninformative observation
Assume $\mu=1$, $\sigma=\sigma_0>0$, $h=h_0$, $a=a_0$ are constants, and $X_0\sim N(z_0,v_0)$. These coefficients satisfy the canonical boundedness conditions. Before maturity, conditionally on observations, \[ \pi_t=N(z_t,v_t),\qquad dz_t=u_tdt,\quad dv_t=\sigma_0^2dt. \tag{5} \] Indeed $O$ and survival are independent of the signal noise, while the control path is known from observations. Thus all uncertainty in the state is its initial Gaussian component plus independent Brownian noise. For a continuous $k$ of at most quadratic growth put $K(z,v)=\mathbb E[k(z+\sqrt v Z)]$, $Z\sim N(0,1)$. The reduced obstacle expression is \[ \min\left\{K-F,\inf_{u\in U} [uF_z+\sigma_0^2F_v+\psi(u)+c+a_0(K-F)]\right\}=0. \tag{6} \] This provides a two-dimensional sufficient state. For deterministic paths $z_t=z_0+\int_0^t u_sds$ and a deterministic voluntary time $s$, the cost is \[ e^{-a_0s}K(z_s,v_0+\sigma_0^2s) +\int_0^s e^{-a_0t}\{\psi(u_t)+c+a_0K(z_t,v_0+\sigma_0^2t)\}dt. \tag{7} \] Observation-based randomization cannot improve the infimum of (7): condition on the whole independent observation path, so each realization supplies a deterministic control path and stopping time, and its cost is at least the infimum over such deterministic choices. Conversely every deterministic choice is admissible. Formula (7) therefore exactly reduces this special case to deterministic control and stopping. It does not solve the stopping boundary for arbitrary $k$.A specific failure of Gaussian closure
Proposition: Let $\mu=0$, $\sigma=\sigma_0>0$, $h=0$, $X_0\sim N(0,v)$ with $v>0$, and $a(x)=a_0+\beta(1+\cos x)$ with $\beta>0$. All canonical coefficient restrictions hold, but the survival posterior does not remain in the Gaussian family on any interval starting at zero.
Proof: The conditional density on survival solves the normalized killed heat equation. At time zero its derivative divided by its Gaussian density is \[
\frac{\sigma_0^2}{2}\left(\frac{x^2}{v^2}-\frac1v\right)
-\beta\{\cos x-\mathbb E\cos(X_0)\}.
\] Every differentiable path of nondegenerate Gaussian densities has a logarithmic derivative which is a polynomial in $x$ of degree at most two. The displayed nonzero cosine term is not such a polynomial. Smooth bounded killing and the heat equation give the displayed density derivative; Gaussian means and variances, if a Gaussian representation existed, would be differentiable by their moment equations. This contradiction proves the assertion. ∎
This obstruction rules out the usual Gaussian closure, not every imaginable finite-dimensional filter. Constructing general posterior obstacle solutions and identifying wider exact finite-dimensional families remain the unresolved parts of the original question.References
- [bgk] V. E. Beneš, G. Gaitsgori and I. Karatzas. Drift Control with Discretionary Stopping for a Diffusion, arXiv:2401.10043v3, Section 5. https://arxiv.org/html/2401.10043v3#S5.