gpt pro 5.2 attempt on Math-672
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Erdős Problem #98
- Formal Restatement.
For a finite set $P\subset\mathbb{R}^2$, write \[ \Delta(P):=\{\|p-q\|:p,q\in P,\ p\ne q\} \] for the set of (nonzero) Euclidean distances determined by pairs of points. Let $\mathcal{G}_n$ be the family of all $n$-point sets $P\subset\mathbb{R}^2$ in general position in the sense:
- no three points of $P$ are collinear;
- no four points of $P$ are concyclic.
Question $\#98$. Does $h(n)/n\to\infty$ as $n\to\infty$?
- Quick literature/context check.
The Erdős Problems page lists this as open (last edited 15 Oct 2025).[ErdosProblems98] It records that Erdős could not even prove $h(n)\ge n$, and that Pach proved an upper bound $h(n)<n^{\log_2 3}$.[ErdosProblems98] It also records a stronger upper bound by Erdős--Füredi--Pach--Ruzsa $1993$: \[ h(n) < n\exp\left(c\sqrt{\log n}\right)\quad\text{for some constant }c>0. \] [ErdosProblems98,EFPR93]
Independently, for arbitrary $n$-point sets (with no general-position hypotheses), Guth and Katz proved that the number of distinct distances is at least on the order of $n/\log n$.[GK15] Since $\mathcal{G}_n$ is a subset of all $n$-point sets, this lower bound applies to $h(n)$ as well.
- Attack plan.
Proof track (toward $h(n)/n\to\infty$). Seek a superlinear lower bound on $|\Delta(P)|$ under the combined restrictions "no three collinear" and "no four concyclic." Natural approaches:
- strengthen incidence-based distinct distance arguments by ruling out rich lines and rich circles;
- "pinned distance" methods: show some point determines $\omega(n)$ distinct distances, then $|\Delta(P)|\ge \omega(n)$.
Disproof track (construct $P\in\mathcal{G}_n$ with $|\Delta(P)|=O(n)$). Try to build a highly structured configuration with many repeated distances while avoiding collinear triples and concyclic quadruples. A key obstacle is that small perturbations typically destroy distance multiplicities.
Phase 1 small cases. Compute/construct $h(n)$ for the smallest $n$ to sanity-check the definition and the general-position constraints.
- Work.
(A) Tiny cases (exact).
Claim 1: $h(3)=1$. Take an equilateral triangle; then $|\Delta(P)|=1$, and clearly no three collinear. Hence $h(3)\le 1$. On the other hand, any three non-collinear points determine at least one distance, so $h(3)=1$.
Claim 2: $h(4)=2$. Upper bound. Let $A,B,C$ be an equilateral triangle of side length $1$, and let $O$ be its circumcenter (which coincides with centroid). Then \[ \|A-B\|=\|B-C\|=\|C-A\|=1,\qquad \|O-A\|=\|O-B\|=\|O-C\|=\frac{1}{\sqrt{3}}. \] Thus $\Delta(\{A,B,C,O\})=\{1,1/\sqrt{3}\}$ has size $2$. The four points are in general position: no three are collinear, and they are not concyclic because the unique circle through $A,B,C$ is the circumcircle centered at $O$, which does not contain $O$. So $h(4)\le 2$.
Lower bound. A set of four planar points cannot have all six pairwise distances equal (the largest equidistant set in $\mathbb{R}^2$ has size $3$), so $h(4)\ne 1$. Therefore $h(4)=2$.
(B) General bounds from the literature.
Lower bound (all $n$). Guth--Katz proved that for any $n$ points in $\mathbb{R}^2$, \[ |\Delta(P)| \ge c\,\frac{n}{\log n} \] for some absolute constant $c>0$.[GK15] Since $\mathcal{G}_n$ is a subset of all $n$-point sets, \[ h(n)=\min_{P\in\mathcal{G}_n}|\Delta(P)| \ge c\,\frac{n}{\log n}. \] This is far from the desired superlinear growth, but it is a rigorous baseline.
Upper bound (general position). Erdős--Füredi--Pach--Ruzsa constructed (for all sufficiently large $n$) $n$-point sets in general position with \[ |\Delta(P)| < n\exp\left(c\sqrt{\log n}\right) \] for some constant $c>0$.[EFPR93,ErdosProblems98] Hence \[ h(n) \le n\exp\left(c\sqrt{\log n}\right). \]
Current gap. To answer "$h(n)/n\to\infty$?" one needs either:
- a lower bound $h(n)\ge n\cdot\omega(1)$ (even $h(n)\ge n\log\log n$ would suffice), or
- a construction showing $h(n)=O(n)$.
- Verification.
The computations for $h(3)$ and $h(4)$ are explicit and verify the general-position constraints. For the general bounds:
- Guth--Katz applies to all point sets, so it applies to $\mathcal{G}_n$ without extra hypotheses.
- EFPR93 is explicitly a construction in general position as quoted on the Erdős Problems page, and thus gives an upper bound on $h(n)$.
- FINAL: UNRESOLVED.
- (i) Strongest fully proved partial result: For all $n$, $h(n)\ge c\,n/\log n$ (Guth--Katz), and there exist general-position sets with $h(n)\le n\exp(c\sqrt{\log n})$ (EFPR93). Also $h(3)=1$ and $h(4)=2$ exactly.
- (ii) Most plausible route forward: Either (a) prove a substantially improved lower bound in general position by combining incidence geometry with the prohibition of 4-point cocircularities, or (b) construct a genuinely linear-distance construction $|\Delta(P)|=O(n)$ while certifying no 3 collinear and no 4 concyclic.
- (iii) First place the proof attempt breaks: Known distinct-distance lower bounds (even with modern polynomial/incidence methods) are essentially linear up to polylog factors; current techniques do not yield superlinear lower bounds from these general-position constraints.
- (iv) What a counterexample would have to look like: An infinite family $P_n\in\mathcal{G}_n$ with $|\Delta(P_n)|\le Cn$ for a constant $C$ independent of $n$.
- Completion estimate.
COMPLETION: 15%.