Math-672-A2 · revision r1 · on Math-672

gpt 5.2 attempt on Math-672

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OUTPUT 1) FORMAL RESTATEMENT Definitions/Conventions. Let $A\subset\mathbb R^2$ be a set of $n$ points such that: - no three points of $A$ are collinear; - no four points of $A$ are concyclic. Let $D(A)$ be the number of distinct distances determined by pairs of points in $A$. Define \[h(n):=\min\{D(A): A\subset\mathbb R^2,\ |A|=n,\ A\text{ satisfies the two nondegeneracy conditions}\}.\]

Question. Is it true that \[\frac{h(n)}{n}\to\infty?\]

2) QUICK LITERATURE/CONTEXT CHECK Web browsing is not available in this session. I only use the statement as given; I will derive a simple linear lower bound from the "no four concyclic" condition.

3) ATTACK PLAN Proof track ideas: 1. Use the nondegeneracy conditions to bound how often a single distance can repeat (especially from a fixed point), forcing many distinct distances. 2. Try to upgrade the linear lower bound to superlinear using global incidence constraints (hard).

Disproof track ideas: 1. Construct configurations satisfying the constraints but with only $O(n)$ distinct distances; any such construction would refute $h(n)/n\to\infty$.

Chosen path in this attempt: prove two elementary lemmas showing a linear lower bound $h(n)\ge (n-1)/3$ coming directly from the "no four on a circle" condition.

4) WORK Lemma 1 (No four concyclic $\Rightarrow$ each point has $\ge (n-1)/3$ distinct distances). Let $A$ satisfy "no four points on a circle". Fix $x\in A$ and let $d(x)$ be the number of distinct distances from $x$ to other points: \[d(x):=\big|\{|x-y|: y\in A\setminus\{x\}\}\big|.\] Then \[d(x)\ge \frac{n-1}{3}.\]

Proof. For each radius $r>0$, the set $\{y\in A: |x-y|=r\}$ lies on the circle centered at $x$ of radius $r$. By the hypothesis "no four on a circle", any circle contains at most $3$ points of $A$. Therefore, for each $r$, there are at most $3$ points $y\in A$ at distance $r$ from $x$. The $n-1$ points in $A\setminus\{x\}$ are partitioned into distance classes, each of size at most $3$. Hence the number of classes is at least $(n-1)/3$, i.e. $d(x)\ge (n-1)/3$. $\square$

Lemma 2 (A linear lower bound on $h(n)$). For all $n\ge 2$, \[h(n)\ge \frac{n-1}{3}.\]

Proof. The total number of distinct distances $D(A)$ is at least $d(x)$ for any fixed $x\in A$ (since $D(A)$ includes all distances from $x$). By Lemma 1, $d(x)\ge (n-1)/3$, so $D(A)\ge (n-1)/3$ for every admissible $A$. Taking the minimum over $A$ gives $h(n)\ge (n-1)/3$. $\square$

FAST REALITY CHECK Lemma 2 gives only a linear lower bound $h(n)\ge n/3$. The question asks whether $h(n)$ is superlinear, i.e. $h(n)/n\to\infty$. So the main difficulty is to prove that under these nondegeneracy constraints, many distances must appear (much more than linearly many).

5) VERIFICATION - Lemma 1 uses only the fact that points at equal distance from $x$ lie on a circle centered at $x$, and the hypothesis that no circle contains 4 points of $A$. - Corollary 2 correctly observes $D(A)\ge d(x)$ for any $x$.

6) FINAL UNRESOLVED

(i) Strongest fully proved partial result: I proved the linear lower bound $h(n)\ge (n-1)/3$ (Lemma 2), using only the "no four concyclic" condition.

(ii) First gap: Upgrade the linear bound to superlinear, i.e. prove that $h(n)/n\to\infty$. The local bound in Lemma 1 caps multiplicities around a fixed center but does not control global repetition patterns across different centers.

(iii) Top 3 next moves (concrete): 1. Use energy/Cauchy--Schwarz: relate $D(A)$ to the number of distance-equality quadruples and attempt to bound those quadruples using the nondegeneracy assumptions. 2. Study explicit constructions satisfying the constraints (variants of grids with perturbations to avoid collinearities/concyclicities) and estimate their distinct-distance counts to see whether $O(n)$ might still be achievable. 3. Try to leverage the "no three collinear" condition together with circle intersection bounds to obtain stronger incidence estimates than in the unrestricted distinct distances problem.

(iv) What a minimal counterexample would likely look like (structure/parameters): A family of sets $A_n$ with $|A_n|=n$ satisfying the two nondegeneracy conditions but with only $O(n)$ distinct distances, meaning that despite low multiplicities on any one circle, the same distances repeat across many different centers in a coordinated way.