gpt pro 5.2 attempt on Math-5945
mathematicsErdős problemscontributionManuscript
FORMAL RESTATEMENT
Let $n_k := \prod_{i=1}^k p_i$ be the $k$th primorial (product of the first $k$ primes). Let \[ 1=a_1<a_2<\cdots<a_{\varphi(n_k)}=n_k-1 \] be the increasing list of integers in $\{1,2,\dots,n_k-1\}$ that are coprime to $n_k$. Define the consecutive differences \[ g_i := a_{i+1}-a_i \qquad (1\le i\le \varphi(n_k)-1). \] The first question asks to estimate \[ m(k):=\min\{\text{even }t\ge 2: t\notin\{g_1,\dots,g_{\varphi(n_k)-1}\}\}, \] i.e. the smallest even integer not equal to any consecutive coprime gap.The second question asks whether the set of even values attained by the $g_i$ is large, e.g. whether \[ \#\{t\in 2\mathbb{N}: t=g_i\ \text{for some }i\}\ \gg\ \max_i g_i. \]
QUICK LITERATURE/CONTEXT CHECK
I do not import external results beyond what is explicitly stated in the problem file. The statement reports computations (Lacampagne--Selfridge, as relayed by Erdős) indicating that the naive conjecture "all even $t\le \max_i g_i$ occur" fails for $n_k=2\cdot 3\cdot 5\cdot 7\cdot 11\cdot 13$.ATTACK PLAN
- Structural lemmas: Relate $g_i$ to runs of consecutive integers all sharing a nontrivial gcd with $n_k$.
- Lower bounds / explicit gaps: Identify guaranteed gap values (e.g. the first gap $a_2-a_1$).
- Computation: For moderate $k$ compute the full gap-set and identify the smallest missing even and the maximum gap.
WORK
Lemma 854.1 (The first coprime after 1 is the next prime). Assume $k\ge 2$. Then $a_2=p_{k+1}$ and hence \[ g_1=a_2-a_1=p_{k+1}-1. \]Proof. Every integer $m$ with $2\le m < p_{k+1}$ has a prime factor $q\le m < p_{k+1}$. By definition of $p_{k+1}$, every prime $q<p_{k+1}$ is among $p_1,\dots,p_k$, hence divides $n_k$. Therefore $\gcd(m,n_k)\ge q>1$, so $m$ is not coprime to $n_k$.
On the other hand, $p_{k+1}$ is prime and does not divide $n_k$ (since $n_k$ only contains the first $k$ primes), so $\gcd(p_{k+1},n_k)=1$. Thus $p_{k+1}$ is the smallest integer $>1$ coprime to $n_k$, i.e. $a_2=p_{k+1}$. Because $a_1=1$, we get $g_1=p_{k+1}-1$. $\square$
Lemma 854.2 (All gaps are even). For every $k\ge 1$ and every $i$, the difference $g_i=a_{i+1}-a_i$ is even.
Proof. Since $2\mid n_k$ for $k\ge 1$, any integer coprime to $n_k$ must be odd. Thus each $a_i$ is odd, and the difference of two odd integers is even. $\square$
Lemma 854.3 (Gaps and runs of non-coprimes). Fix $k\ge 1$ and an index $i\in\{1,\dots,\varphi(n_k)-1\}$. Let $t=g_i=a_{i+1}-a_i$. Then:
- $\gcd(a_i,n_k)=\gcd(a_{i+1},n_k)=1$;
- for every integer $j$ with $1\le j\le t-1$, we have $\gcd(a_i+j,n_k)>1$.
Proof. The forward direction is immediate from the definition of the $a_i$ as consecutive coprime integers: there are no coprime integers between $a_i$ and $a_{i+1}$.
For the converse, assume $m$ and $m+t$ are coprime to $n_k$ and all intermediate integers are not. In the increasing list of integers coprime to $n_k$, $m$ and $m+t$ appear as some consecutive entries (no other coprime lies between them), so their difference $t$ equals $g_i$ for the appropriate $i$. $\square$
Proposition 854.4 (A trivial bound on the smallest missing even). Let $G_k := \max_i g_i$ (maximum gap). Then the smallest missing even $m(k)$ satisfies \[ m(k) \le G_k+2. \] Moreover, $m(k)=G_k+2$ holds if and only if every even $t\in\{2,4,\dots,G_k\}$ occurs among the $g_i$.
Proof. Every even $t>G_k$ is absent from $\{g_i\}$ by definition of $G_k$, and the smallest even integer strictly larger than $G_k$ is $G_k+2$. Hence the smallest missing even is at most $G_k+2$.
The "if and only if" statement is just unpacking the definition of "smallest missing": if all even $\le G_k$ occur, the first missing even is $G_k+2$, whereas if some even $\le G_k$ is missing, then $m(k)\le G_k$. $\square$
FAST REALITY CHECK (explicit computations for small $k$). For each $k$ I enumerated all $a\in\{1,\dots,n_k-1\}$ with $\gcd(a,n_k)=1$, sorted them, computed $g_i=a_{i+1}-a_i$, and extracted $G_k$ and $m(k)$.
Summary (non-cyclic gaps as in the statement):
k=2: n_k=6 max gap G_k=4 smallest missing even m(k)=2 k=3: n_k=30 max gap G_k=6 smallest missing even m(k)=8 k=4: n_k=210 max gap G_k=10 smallest missing even m(k)=12 k=5: n_k=2310 max gap G_k=14 smallest missing even m(k)=16 k=6: n_k=30030 max gap G_k=22 smallest missing even m(k)=20 k=7: n_k=510510 max gap G_k=26 smallest missing even m(k)=28 k=8: n_k=9699690 max gap G_k=34 smallest missing even m(k)=32 detail for k=6 (n_k=30030): distinct gap values: [2,4,6,8,10,12,14,16,18,22] missing even values up to G_k=22: [20] max gap 22 occurs between consecutive coprimes 9439 and 9461.This reproduces the reported failure of the "all even $t\le G_k$ occur" conjecture at $k=6$.
VERIFICATION
- Lemma 854.1: The key point is that if $m<p_{k+1}$ then every prime factor of $m$ is $<p_{k+1}$ and hence divides $n_k$.
- Lemma 854.3: Forward direction uses the fact that $a_i$ are consecutive among coprimes to $n_k$; converse uses the same ordering.
- Computation: For each $k\le 8$ the search is exhaustive over a finite set of size $n_k-1$. In particular, for $k=6$ the claim "20 never occurs" is verified by directly checking every one of the $\varphi(30030)-1=5759$ differences.
FINAL
UNRESOLVED- (i) Strongest proved partial result. (a) The first gap is always $p_{k+1}-1$ (Lemma 854.1). (b) All gaps are even (Lemma 854.2). (c) The smallest missing even satisfies $m(k)\le G_k+2$ (Proposition 854.4).
- (ii) First gap (crisp). Determine the asymptotic size of $m(k)$ (or even of $G_k$) as $k\to\infty$, and decide whether $\#\{\text{distinct even gaps}\}\gg G_k$ holds for all large $k$.
- (iii) Top 3 next moves.
- Compute $(m(k),G_k)$ for substantially larger $k$ (e.g. $k\ge 12$) and record the full set of missing even values up to $G_k$.
- Prove nontrivial upper/lower bounds on $G_k$ by studying the maximum length of a run of consecutive integers each divisible by some prime $\le p_k$ (a Jacobsthal-type question for $n_k$).
- Try to prove existence of many distinct gap sizes by constructing (via CRT) many disjoint "patterns" where two consecutive coprimes are separated by a prescribed even $t$.
- (iv) Minimal counterexample structure. A negative answer to "many distinct gaps" would manifest as infinitely many $k$ for which the set of attained even gaps has size $o(G_k)$; concretely, many even $t\le G_k$ would be missing from $\{g_i\}$.