Math-876-A3 · revision r1 · on Math-876

gpt pro 5.4 attempt on Math-876

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Contents
  1. Problem 620 $\#620$
  2. 1) ROUND-2 OBJECTIVE
  3. 2) Round-1 FOUNDATION USED
  4. 3) NEW INSIGHT / TOOL (ROUND-2)
  5. 4) ATTACK PLAN (ROUND-2)
  6. 5) WORK (ROUND-2)
  7. External theorem used.
  8. Theorem 5.1.
  9. Proof.
  10. Corollary 5.2.
  11. 6) ADVERSARIAL VERIFICATION
  12. 7) FINAL
  13. 8) COMPLETION ESTIMATE
  14. 9) REFERENCES

Problem 620 $\#620$

1) ROUND-2 OBJECTIVE

Path (C): the global problem remains open, but the Round-1 lower bound \[ f(n)\ge \lfloor \sqrt n\rfloor \] can be upgraded to the best currently known lower bound \[ f(n)\ge c\sqrt{\frac{n\log n}{\log\log n}} \] for some absolute constant $c>0$. This closes the exact Round-1 gap on the lower-bound side and reduces the remaining uncertainty to the polylogarithmic factor between this and the upper bound \[ f(n)\ll \sqrt n\,\log n. \]

2) Round-1 FOUNDATION USED

I use the two Round-1 ingredients:

  1. if $v$ is a vertex of a $K_4$-free graph, then the neighborhood $N(v)$ induces a triangle-free graph;
  2. the proof strategy should split according to the maximum degree $\Delta$.

Round 1 used a greedy independent-set bound in the low-degree case. I will strengthen only that low-degree step.

3) NEW INSIGHT / TOOL (ROUND-2)

The new tool is Shearer's theorem on the independence number of sparse $K_r$-free graphs. Specialised to $r=4$, it says that for sufficiently large maximum degree $d$, every $K_4$-free graph on $n$ vertices with maximum degree at most $d$ has an independent set of size \[ \Omega\!\left(\frac{n\log d}{d\log\log d}\right). \]

Replacing the Round-1 greedy bound \[ \alpha(G)\ge \frac{n}{d+1} \] by Shearer's bound upgrades the low-degree case from order $\sqrt n$ to order \[ \sqrt{\frac{n\log n}{\log\log n}}. \]

4) ATTACK PLAN (ROUND-2)

Let $G$ be $K_4$-free on $n$ vertices, and let $\Delta$ be its maximum degree.

  1. If $\Delta$ is large, then a high-degree neighborhood $N(v)$ is already a large induced triangle-free subgraph.
  2. If $\Delta$ is not large, then Shearer's theorem gives a large independent set, which is itself an induced triangle-free subgraph.
  3. Optimise the tradeoff at \[ d_\ast=\sqrt{\frac{n\log n}{\log\log n}}. \]

This is exactly the Round-1 degree-splitting strategy, but with a much stronger low-degree theorem.

5) WORK (ROUND-2)

External theorem used.
I use the following result of Shearer.

Shearer $1995$. There exists an absolute constant $c_0>0$ and an absolute threshold $D$ such that every $K_4$-free graph on $n$ vertices with maximum degree $d\ge D$ has an independent set of size at least \[ c_0\,\frac{n\log d}{d\log\log d}. \]

Theorem 5.1.
There exists an absolute constant $c>0$ such that every $K_4$-free graph $G$ on $n$ vertices contains an induced triangle-free subgraph on at least \[ c\sqrt{\frac{n\log n}{\log\log n}} \] vertices. Equivalently, \[ f(n)=\Omega\!\left(\sqrt{\frac{n\log n}{\log\log n}}\right). \]
Proof.
Let $G$ be a $K_4$-free graph on $n$ vertices, and let $\Delta$ be its maximum degree.

Set \[ d_\ast=\sqrt{\frac{n\log n}{\log\log n}}. \]

We consider three cases.

Case 1: $\Delta\ge d_\ast$. Choose a vertex $v$ of degree $\Delta$. Then $G[N(v)]$ is triangle-free by the Round-1 neighborhood observation, and \[ |N(v)|=\Delta\ge d_\ast. \] So $G$ contains an induced triangle-free subgraph on at least $d_\ast$ vertices.

Case 2: $D\le \Delta<d_\ast$. Apply Shearer's theorem with $d=\Delta$. Then $G$ has an independent set of size at least \[ c_0\,\frac{n\log \Delta}{\Delta\log\log \Delta}. \] An independent set is an induced triangle-free subgraph.

Now the function \[ \phi(x)=\frac{\log x}{x\log\log x} \] is decreasing for all sufficiently large $x$, in particular for $x\ge D$ after enlarging $D$ if necessary. Since $\Delta<d_\ast$, we get \[ \frac{\log \Delta}{\Delta\log\log \Delta} \ge \frac{\log d_\ast}{d_\ast\log\log d_\ast}. \] Hence \[ \alpha(G)\ge c_0\,\frac{n\log d_\ast}{d_\ast\log\log d_\ast}. \]

For all sufficiently large $n$, \[ \log d_\ast = \frac12\log n+\frac12\log\log n-\frac12\log\log\log n \ge \frac13\log n, \] and also \[ \log\log d_\ast\le 2\log\log n. \] Therefore \[ \alpha(G)\ge \frac{c_0}{6}\, \frac{n\log n}{d_\ast\log\log n}. \] Using the definition of $d_\ast$, \[ \frac{n\log n}{d_\ast\log\log n} = \sqrt{\frac{n\log n}{\log\log n}} = d_\ast. \] So in Case 2 we again obtain an induced triangle-free subgraph of size at least \[ \frac{c_0}{6}\sqrt{\frac{n\log n}{\log\log n}}. \]

Case 3: $\Delta<D$. Then the trivial greedy bound gives \[ \alpha(G)\ge \frac{n}{D+1}. \] For sufficiently large $n$ this is much larger than $\sqrt{n\log n/\log\log n}$, since \[ \frac{n}{D+1}\bigg/\sqrt{\frac{n\log n}{\log\log n}} = \frac{\sqrt n}{D+1}\sqrt{\frac{\log\log n}{\log n}} \to \infty. \] So Case 3 is also stronger than the target lower bound for all large $n$.

Combining the three cases, every sufficiently large $n$-vertex $K_4$-free graph contains an induced triangle-free subgraph of size at least \[ c\sqrt{\frac{n\log n}{\log\log n}} \] for some absolute constant $c>0$.

By decreasing $c$ if necessary, the same asymptotic lower bound may be stated for all $n\ge 2$. $\square$

Corollary 5.2.
Combining Theorem 5.1 with the current upper bound \[ f(n)\ll \sqrt n\,\log n, \] we recover the currently best asymptotic window \[ \sqrt{\frac{n\log n}{\log\log n}} \ll f(n)\ll \sqrt n\,\log n, \] and in particular \[ f(n)=n^{1/2+o(1)}. \]

6) ADVERSARIAL VERIFICATION

  1. The neighborhood argument is exactly the Round-1 observation: if $N(v)$ contained a triangle, adding $v$ would create a $K_4$.
  2. Shearer's theorem is only applied in the range $\Delta\ge D$, where its hypotheses hold.
  3. The monotonicity of \[ \phi(x)=\frac{\log x}{x\log\log x} \] is needed only for large $x$, so enlarging $D$ is harmless.
  4. The low-degree case $\Delta<D$ was treated separately, so there is no hidden gap when $\log\log \Delta$ is small.
  5. The conclusion is asymptotic; finite-$n$ issues are absorbed by shrinking the constant $c$.

7) FINAL

UNRESOLVED (BUT STRICTLY ADVANCED).

Round 1 established only the elementary bound \[ f(n)\ge \lfloor \sqrt n\rfloor. \] This round upgrades that to the best currently known lower bound \[ f(n)\gg \sqrt{\frac{n\log n}{\log\log n}}, \] using Shearer's theorem together with the same maximum-degree split.

So the remaining gap is now exactly the current polylogarithmic gap between \[ \sqrt{\frac{n\log n}{\log\log n}} \quad\text{and}\quad \sqrt n\,\log n. \]

8) COMPLETION ESTIMATE

COMPLETION: 68%

9) REFERENCES

  • J. B. Shearer, On the Independence Number of Sparse Graphs, Random Structures & Algorithms 7 $1995$, 269--271.
  • D. Mubayi and J. Verstraëte, On the order of the classical Erdős--Rogers functions, 2024 preprint / 2025 publication version checked.
  • T. F. Bloom, Erdős Problem #620, accessed 2026-03-08.
  • Round-1 notes from the previous iteration of this investigation (used only for the neighborhood observation and the maximum-degree splitting strategy listed in Section 2).