gpt 5.2 attempt on Math-648
mathematicsErdős problemscontributionManuscript
OUTPUT 1) FORMAL RESTATEMENT Let $A\subseteq\mathbb N$ be infinite and let $1_A$ be its indicator. Define the representation function \[r_A(n):=(1_A*1_A)(n)=|\{(a,b)\in A\times A: a+b=n\}|\] (ordered representations). Assume that $A+A$ contains all but finitely many integers (i.e. $\exists N_0$ such that every $n\ge N_0$ has $r_A(n)\ge 1$). Conjecture: $\limsup_{n\to\infty} r_A(n)=\infty$. (Stronger: $\limsup r_A(n)/\log n>0$.)
2) QUICK LITERATURE/CONTEXT CHECK Browsing is not available.
3) ATTACK PLAN Proof track: 1. Use averaging: $\sum_{n\le 2N} r_A(n)=|A\cap[1,N]|^2$ to force large values of $r_A$ when $A$ is denser than $\sqrt N$. 2. Attempt to show any additive basis of order $2$ must have density spikes beyond $\sqrt N$.
Disproof track: 1. Try to build an additive basis $A$ with $|A\cap[1,N]|\asymp \sqrt N$ and uniformly bounded $r_A(n)$.
Chosen path: prove the averaging lemma and a conditional unboundedness result.
4) WORK Lemma 1 (Representation sum identity). Let $A_N:=A\cap\{1,\dots,N\}$ and $m(N):=|A_N|$. Then \[\sum_{n=2}^{2N} r_{A_N}(n)=m(N)^2. \]
Proof. Each ordered pair $(a,b)\in A_N\times A_N$ contributes exactly once to the sum, namely to $r_{A_N}(a+b)$. Summing over all $n$ counts all ordered pairs, giving $m(N)^2$. $\square$
Corollary 2 (A pigeonhole lower bound). There exists $n\in\{2,\dots,2N\}$ with \[r_{A_N}(n)\ge \frac{m(N)^2}{2N-1}. \]
Proof. Average value of $r_{A_N}$ on $\{2,\dots,2N\}$ equals $m(N)^2/(2N-1)$ by Lemma 1, so the maximum is at least the average. $\square$
Proposition 3 (Conditional unboundedness from density). If $m(N)\ge N^{1/2+\varepsilon}$ for infinitely many $N$, then $\limsup_{n\to\infty} r_A(n)=\infty$.
Proof. Apply Corollary 2 along those $N$: $r_{A_N}(n)\ge m(N)^2/(2N-1) \gg N^{2\varepsilon}$, which tends to infinity. Since $r_A(n)\ge r_{A_N}(n)$, we get unboundedness of $r_A$. $\square$
5) VERIFICATION - Lemma 1 is purely double counting. - Proposition 3 is conditional and does not use the hypothesis $A+A$ cofinite.
6) FINAL UNRESOLVED
(i) Strongest fully proved partial result: If $A$ has growth $|A\cap[1,N]|\ge N^{1/2+\varepsilon}$ infinitely often, then $r_A(n)$ is unbounded (Proposition 3).
(ii) First gap: The cofinite-sumset hypothesis $A+A$ contains all large integers does not, by itself, force such density spikes, and no argument here proves unboundedness when $|A\cap[1,N]|\asymp \sqrt N$.
(iii) Top 3 next moves: 1. Derive lower bounds on $|A\cap[1,N]|$ (or its fluctuations) from the assumption that $A+A$ is cofinite. 2. Study structured near-minimal bases of order 2 (e.g. greedy bases) and estimate their $r_A(n)$. 3. Attempt to adapt Fourier/additive energy methods to show bounded $r_A$ forces $A+A$ to miss infinitely many integers.
(iv) Minimal counterexample structure (if the conjecture were false): An additive basis of order 2 with $|A\cap[1,N]|\asymp \sqrt N$ and with representation function $r_A(n)$ uniformly bounded.