gpt pro 5.2 attempt on Math-728
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Contents
Erdős Problem #244
1) FORMAL RESTATEMENT
Fix a real number $C>1$. Define the "geometric-floor" sequence \[ t_k \coloneqq \lfloor C^k\rfloor\qquad (k\in\mathbb{Z}_{\ge 0}), \] and the set \[ \mathcal{S}_C \coloneqq \{\, p + t_k : p\in\mathcal{P},\ k\in\mathbb{Z}_{\ge 0}\,\}\subseteq\mathbb{N}, \] where $\mathcal{P}$ is the set of primes and $\lfloor\cdot\rfloor$ is the floor function.For $x\ge 1$ write \[ \mathcal{S}_C(x) \coloneqq \#\left(\mathcal{S}_C\cap\{1,2,\dots,\lfloor x\rfloor\}\right). \] The (lower) asymptotic density of $\mathcal{S}_C$ is \[ \underline{d}(\mathcal{S}_C) \coloneqq \liminf_{x\to\infty} \frac{\mathcal{S}_C(x)}{x}. \]
Question (Romanoff--Kalmár type). Is $\underline{d}(\mathcal{S}_C)>0$ for every real $C>1$?
Remark on ambiguity. The original phrasing "has density $>0$" could mean (i) the natural density exists and is positive, or (ii) the lower asymptotic density is positive. The currently recorded results (Romanoff for integer $C$; Ding for almost all real $C$) are naturally stated in terms of positive lower asymptotic density, so I interpret the question as above.
2) QUICK LITERATURE/CONTEXT CHECK
- For integer $C=a\ge 2$, the set $\{p+a^k\}$ has positive lower asymptotic density by Romanoff (often called Romanov's theorem) [Romanoff1934]. See also the modern summary "Romanov's theorem" [WikipediaRomanov].
- The Erdős Problems database page for #244 records: Romanoff's theorem for integer $C$, and that Y. Ding $2025$ proved positivity of the lower density for almost all $C>1$ (in the sense of Lebesgue measure) [ErdosProblems244,Ding2025].
- As of the last edit recorded on the Erdős Problems site (Oct 28, 2025), the statement "for every $C>1$" remains open [ErdosProblems244].
3) ATTACK PLAN
A classical approach for $C\in\mathbb{Z}_{\ge 2}$ (Romanoff) is:- Let $r(n)$ count representations $n=p+a^k$.
- Use Cauchy--Schwarz: $\#\{n\le x:r(n)>0\}\ge \frac{(\sum_{n\le x} r(n))^2}{\sum_{n\le x} r(n)^2}$.
- Estimate $\sum r(n)$ from below and bound $\sum r(n)^2$ from above using sieve bounds for prime pairs with fixed differences $a^{k_2}-a^{k_1}$.
For general real $C>1$, one would need to control differences \[ \lfloor C^{k_2}\rfloor-\lfloor C^{k_1}\rfloor \] uniformly in $k_1,k_2$ and prevent exceptional $C$ for which these differences have "too many" small prime factors (making sieve upper bounds too large) or create excessive overlap.
A disproof strategy (if false) would seek a specific $C$ where the set of shifts $\{\lfloor C^k\rfloor\}$ forces strong congruence restrictions so that $\mathcal{S}_C$ misses a positive proportion of residue classes for infinitely many moduli; no such explicit $C$ is currently known to me.
4) WORK
4.1 A trivial but rigorous lower bound
Even without Romanoff/Ding, one always has a nontrivial growth lower bound (though it only gives density $0$):Consequently $\mathcal{S}_C(x)/x \ge \pi(x-1)/x \sim 1/\log x$ as $x\to\infty$, so this does not approach a positive constant.
4.2 Small computational sanity checks (not proofs)
I computed the empirical density \[ \frac{\mathcal{S}_C(X)}{X} \] for a few sample values of $C$ and cutoffs $X\in\{2\cdot 10^5,10^6\}$. The computation used:- all distinct shifts $t_k=\lfloor C^k\rfloor\le X$;
- all primes $p\le X$;
- a boolean array to mark $p+t_k\le X$.
| $C$ | $\mathcal{S}_C(2\cdot 10^5)/(2\cdot 10^5)$ | $\mathcal{S}_C(10^6)/(10^6)$ |
| $2$ | $0.554360$ | $0.538970$ |
| $1.5$ | $0.883265$ | $0.899666$ |
| $\sqrt{2}$ | $0.856375$ | $0.864454$ |
| $e$ | $0.672595$ | $0.665399$ |
| $1.1$ | $0.999945$ | (not computed at $10^6$) |
These values are consistent with the intuition that as $C\downarrow 1$, the shifts $\lfloor C^k\rfloor$ take many small values and the union of translates of the primes covers most integers up to moderate $X$. For larger $C$ there are fewer shifts and the observed density drops.
5) VERIFICATION
- The proof of the lemma is straightforward and uses only that $t_0=1$.
- The computations were double-checked for off-by-one issues by ensuring (i) primes were generated up to $X$, (ii) only shifts $\le X$ were used, and (iii) only sums $p+t_k\le X$ were marked.
- The computational results are included only as heuristic evidence; they do not address the limiting density as $X\to\infty$.
6) FINAL
UNRESOLVED.- Strongest fully proved partial result obtained here: For every $C>1$, the counting function satisfies $\mathcal{S}_C(x)\ge \pi(x-1)$ for all $x\ge 2$ (Lemma above), hence $\mathcal{S}_C(x)\gg x/\log x$.
- First gap preventing a full solution: One needs a uniform lower bound $\mathcal{S}_C(x)\ge \delta x$ for all large $x$ with some $\delta=\delta(C)>0$. Achieving this requires controlling overlaps between the shifted prime sets $\{p+\lfloor C^k\rfloor\}$ across different $k$, typically via second-moment/sieve estimates. I did not obtain such an overlap bound for an arbitrary fixed real $C>1$.
- Most promising next move: Attempt to adapt Romanoff's Cauchy--Schwarz/second-moment method to the shift sequence $\lfloor C^k\rfloor$ for an arbitrary fixed $C$. The key technical step is bounding the number of solutions to $p_1-p_2=\lfloor C^{k_2}\rfloor-\lfloor C^{k_1}\rfloor$ with $p_1,p_2$ prime using sieve bounds, and then summing these bounds over $(k_1,k_2)$.
- Smallest plausible counterexample (if false): A candidate would be a special constant $C$ for which the differences $\lfloor C^{k_2}\rfloor-\lfloor C^{k_1}\rfloor$ are unusually "smooth" (have many small prime factors) for many pairs $(k_1,k_2)$, inflating sieve upper bounds and potentially allowing the second-moment argument to fail. I do not know any explicit $C$ with this property.