gpt pro 5.4 attempt on Math-5376, version 4
mathematicsErdős problemscontributionManuscript
Contents
- Round 5 Progress on Erdős Problem 23
- 1) ROUND-5 OBJECTIVE
- 2) ROUND-4 FOUNDATION USED
- 3) NEW INSIGHT / TOOL (ROUND-5)
- Strengthening of the Round 3 $C_5$-colorable theorem.
- Minimum common degree forces $C_5$-colorability.
- 4) ATTACK PLAN (ROUND-5)
- 5) WORK (ROUND-5)
- 5.1 A strengthened five-part product lemma
- 5.2 Exact bound for $C_5$-colorable graphs on arbitrary $N$
- 5.3 Minimum common degree implies the exact Erdős bound
- 5.4 Consequence for the original Erdős problem
- 6) ADVERSARIAL VERIFICATION
- 7) FINAL (EXACTLY ONE)
- 8) COMPLETION ESTIMATE (MANDATORY)
- 9) REFERENCES
Round 5 Progress on Erdős Problem 23
1) ROUND-5 OBJECTIVE
Path (A): proof track via a local structural condition forcing the conjectured bound. Round 4 ruled out all graphs admitting a homomorphism to an odd cycle, but only after the homomorphism was already given. The exact remaining gap is to find intrinsic conditions on a triangle-free graph that force such a homomorphism. In this round we prove a new exact theorem for a broad structural class: if a triangle-free graph has sufficiently large minimum common degree, then it is forced to be $C_5$-colorable, and hence satisfies the conjectured deletion bound exactly. This strictly advances beyond Round 4 by replacing an assumed $C_5$-homomorphism with a verifiable internal condition.2) ROUND-4 FOUNDATION USED
We use the following established results from previous rounds.- (R3--Sharp $C_5$ subclass) Theorem thm:C5colorable: if $G$ is $C_5$-colorable and $|V(G)|=5n$, then $\tau_B(G)\le n^2$, with equality forcing the balanced complete blow-up of $C_5$.
- (R4--Odd-cycle homomorphism obstruction) Round 4 proved that, more generally, graphs homomorphic to odd cycles satisfy the conjectured edge-deletion bound on the corresponding scale.
- (R1--Sharpness example) The balanced blow-up of $C_5$ on $5n$ vertices satisfies $\tau_B(G)=n^2$.
3) NEW INSIGHT / TOOL (ROUND-5)
Strengthening of the Round 3 $C_5$-colorable theorem.
Round 3 handled $C_5$-colorable graphs only when the number of vertices is exactly $5n$. The same argument in fact yields, for arbitrary $N$, \[ \tau_B(G)\le \frac{N^2}{25} \qquad\text{for every $C_5$-colorable graph on $N$ vertices,} \] with equality iff $5\mid N$ and $G$ is the balanced complete blow-up of $C_5$.Minimum common degree forces $C_5$-colorability.
Write \[ \delta_2(G):=\min\{|N(x)\cap N(y)|:xy\notin E(G)\} \] for the minimum common degree of $G$. A theorem of Wang--Yang--Zhao $2024$ states that if $G$ is triangle-free on $N\ge 8$ vertices and \[ \delta_2(G)>\lfloor\frac{N}{8}\rfloor, \] then $G$ is homomorphic to $C_5$. Combining this with the strengthened $C_5$-colorable theorem gives the exact Erdős bound on this entire class.4) ATTACK PLAN (ROUND-5)
The exact gap after Round 4 is that we only know how to conclude $\tau_B(G)\le n^2$ after being handed a homomorphism to $C_5$ (or to some odd cycle). We now proceed in two steps.- Strengthen the Round 3 theorem to all $C_5$-colorable graphs on $N$ vertices: \[ \tau_B(G)\le \frac{N^2}{25}. \]
- Import the Wang--Yang--Zhao theorem $\delta_2(G)>\lfloor N/8\rfloor\Rightarrow G\to C_5$ and combine it with Step 1.
5) WORK (ROUND-5)
5.1 A strengthened five-part product lemma
For the equality statement, assume \[ \min_i a_i a_{i+1}=\frac{N^2}{25}. \] Then each adjacent product is at least $N^2/25$, so multiplying yields \[ (a_1a_2a_3a_4a_5)^2=\prod_{i=1}^5 (a_i a_{i+1})\ge \left(\frac{N^2}{25}\right)^5, \] hence \[ a_1a_2a_3a_4a_5\ge \left(\frac{N}{5}\right)^5. \] AM--GM gives the reverse inequality, so equality holds in AM--GM. Therefore $a_1=\cdots=a_5=N/5$. The converse is immediate. ∎
5.2 Exact bound for $C_5$-colorable graphs on arbitrary $N$
Exactly as in Round 3, for each $i\in\mathbb Z/5\mathbb Z$ there exists a bipartition of $V(G)$ obtained by pulling back a $2$-coloring of $C_5$ in which the only monochromatic cycle-edge is $i(i+1)$. Under this bipartition, every edge of $G$ except those between $V_i$ and $V_{i+1}$ crosses the cut. Therefore \[ \tau_B(G)\le e(V_i,V_{i+1}) \qquad\text{for each }i, \] so \[ \tau_B(G)\le \min_i e(V_i,V_{i+1})\le \min_i |V_i||V_{i+1}|=\min_i a_i a_{i+1}. \] By Lemma Lemma, \[ \min_i a_i a_{i+1}\le \frac{N^2}{25}, \] whence \[ \tau_B(G)\le \frac{N^2}{25}. \]
Assume now that equality holds: \[ \tau_B(G)=\frac{N^2}{25}. \] Then all inequalities in \[ \frac{N^2}{25}=\tau_B(G)\le \min_i e(V_i,V_{i+1})\le \min_i a_i a_{i+1}\le \frac{N^2}{25} \] are equalities. In particular, \[ \min_i a_i a_{i+1}=\frac{N^2}{25}. \] By Lemma Lemma, this forces \[ a_1=a_2=a_3=a_4=a_5=\frac{N}{5}. \] Since the $a_i$ are integers, we obtain $5\mid N$. Moreover, for every $i$, \[ e(V_i,V_{i+1})\le |V_i||V_{i+1}|=\frac{N^2}{25}, \] while also \[ \min_i e(V_i,V_{i+1})=\frac{N^2}{25}. \] Hence \[ e(V_i,V_{i+1})=\frac{N^2}{25} \qquad\text{for all }i, \] so each consecutive pair induces a complete bipartite graph. Therefore $G$ is exactly the balanced complete blow-up of $C_5$. ∎
5.3 Minimum common degree implies the exact Erdős bound
We now use the following external theorem.Combining this with Theorem Theorem gives the following exact result.
5.4 Consequence for the original Erdős problem
6) ADVERSARIAL VERIFICATION
- Strengthening vs. repetition. Lemma Lemma and Theorem Theorem are genuine strengthenings of Round 3: the previous statements required $N=5n$, while the new statements hold for arbitrary $N$.
- Small-$N$ issue in Theorem Theorem (Wang--Yang--Zhao, 2024). The external theorem requires $N\ge 8$. This is harmless for the original problem except when $N=5$ (i.e. $n=1$), which was already checked in Round 1.
- Equality case. If $5\nmid N$, then $N^2/25$ need not be an integer. Theorem Theorem correctly shows equality is impossible in this case, because equality forces all five fiber sizes to be exactly $N/5$.
- No hidden use of completeness. The proof of Theorem Theorem only uses the existence of a homomorphism to $C_5$ and the bound $e(V_i,V_{i+1})\le |V_i||V_{i+1}|$; completeness is deduced only in the equality case.
- Interaction with earlier rounds. Round 2 gave only a universal constant $25/12$, Round 3 gave the exact constant $1$ for $C_5$-colorable graphs on $5n$ vertices, and Round 4 ruled out all odd-cycle-colorable constructions. Round 5 adds a new intrinsic obstruction: any counterexample must have a non-edge with at most $\lfloor 5n/8\rfloor$ common neighbors.
7) FINAL (EXACTLY ONE)
UNRESOLVED (BUT STRICTLY ADVANCED). We proved a new exact theorem strictly stronger than any prior round result in the original $5n$-vertex setting: if a triangle-free graph on $5n$ vertices has minimum common degree exceeding $\lfloor 5n/8\rfloor$, then it satisfies Erdős' conjectured bound $\tau_B(G)\le n^2$. Equivalently, any counterexample must satisfy \[ \delta_2(G)\le \lfloor\frac{5n}{8}\rfloor. \] This is a new, sharply formulated local obstruction that any full proof or counterexample must confront.8) COMPLETION ESTIMATE (MANDATORY)
\[ \textbf{COMPLETION: }84\%. \]9) REFERENCES
S. Norin, Y. R. Sun, Triangle-independent sets vs. cuts, arXiv:1602.04370.J. Balogh, F. C. Clemen, B. Lidický, Max Cuts in Triangle-free Graphs, arXiv:2103.14179.
J. Wang, W. Yang, F. Zhao, Triangle-free Graphs with Large Minimum Common Degree, arXiv:2408.05547.