GPT 6 Astra Ultra attempt on Math-645
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Erdős Problem #17: independent continuation
Date: 2026-09-23. Research attempt; no claim of a new published result.1) TARGET AND SOURCE AUDIT
A prime $p$ is cluster if every even $2\le n\le p-3$ is a difference of two primes at most $p$. Are infinitely many primes cluster?All supplied versions considered: 17.tex. The source proves simultaneous CRT obstructions for any fixed finite set of composite offsets and a necessary preceding gap of at most six. I do not promote these obstructions to a proof about all sufficiently large primes.
2) WORK
An exact moving-offset hitting condition.
For a prime $p>3$, define the set of backward prime offsets \[ D_p=\{p-r:r\le p\text{ prime}\}. \] Then $p$ is cluster if and only if every odd composite $m$ with $9\le m\le p-2$ satisfies \[ D_p\cap\{m-q:q\le m\text{ prime}\}\ne\varnothing. \tag{1} \] Indeed set $n=p-m$. Any witness $n=r-q$ forces $q\le m$ and $p-r=m-q$; conversely an intersection supplies those two primes. Prime $m\ge3$ is covered by $r=p,q=m$, so only composite offsets remain. This establishes both directions, including the moving range up to $p-2$.For $p>17$, the first two conditions in $1$ require \[ D_p\cap\{2,4,6\}\ne\varnothing,\quad D_p\cap\{2,4,8,10,12\}\ne\varnothing. \] The omitted $q=2$ choices give even upper numbers greater than two. Thus if neither $p-2$ nor $p-4$ is prime, cluster forces $p-6$ prime and at least one of $p-8,p-10,p-12$ prime. This is a two-offset constraint stronger than the source's single necessary gap test.
A reproducible exhaustive check, verification/batch_2_checks.py, uses trial division and all pair differences for every prime at most 500. It finds 65 cluster primes, with largest 491, and checks the preceding-gap necessity for each. This is finite evidence only.
3) ADVERSARIAL VERIFICATION
The CRT argument fixes offsets before choosing $p$. Condition $1$ ranges over offsets depending on $p$, so the quantifiers cannot be interchanged. Prime $2$ is included by the program under the vacuous-range definition; excluding it changes no infinitude question.4) FINAL
UNRESOLVED. The required simultaneous covering of all composite $m\le p-2$ remains unproved for infinitely many $p$. The local constraints and finite computation neither establish finiteness nor infinitude.5) SOURCES CHECKED
All of17.tex was read. The official statement URL https://www.erdosproblems.com/17 returned 403 on this date; the exact definition above is the supplied one. No unverified external sieve theorem is invoked.