GPT 6 Astra Ultra attempt on Math-6204
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Erdős Problem 1150 --- GPT 6 Astra Ultra partial attempt
FORMAL RESTATEMENT
Does there exist an absolute constant $c>0$ and an integer $n_0$ such that, whenever $n\geq n_0$ and \[ P(z)=\sum_{j=0}^n\epsilon_jz^j,\qquad \epsilon_j\in\{-1,1\}, \] one has $\max_{|z|=1}|P(z)|>(1+c)\sqrt n$?CONTEXT AND SCOPE
This replaces the earlier statement-only record with an elementary mathematical attempt. The arguments below establish only their stated partial results; no novelty or full solution is claimed.ATTACK PLAN AND WORK
Let $N=n+1$ and $c_k=\sum_{j=0}^{n-k}\epsilon_j\epsilon_{j+k}$ for $1\le k\le n$. Orthogonality on the unit circle gives \[ \int |P|^2=N,\qquad \int |P|^4=N^2+2\sum_{k=1}^n c_k^2, \tag{1} \] where both integrals use normalized arc measure. Indeed $|P(e^{it})|^2=N+\sum_{k=1}^n c_k(e^{ikt}+e^{-ikt})$, so $1$ follows by taking the constant Fourier coefficients. If $M=\max_{|z|=1}|P(z)|$, then $\int|P|^4\le M^2\int|P|^2$, and hence \[M^2\ge N+\frac2N\sum_{k=1}^n c_k^2.\tag{2}\] The parity relation $c_k\equiv N-k\pmod2$ forces at least $\lceil n/2\rceil$ of these integer correlations to have square at least one. Thus $M^2\ge N+2\lceil n/2\rceil/N$.This improves the bare $L^2$ bound only additively. A sufficient new input would be a uniform bound $\sum c_k^2\ge\eta n^2$ for an absolute $\eta>0$; $2$ would then give a fixed multiplicative improvement over $\sqrt n$. No such bound is proved here. It is a sufficient route, not an equivalence: a large supremum can also be concentrated on a small arc without large fourth moment.