Math-1055-A1 · revision r1 · on Math-1055

gpt 6 astra ultra attempt on Math-1055

Exploration · LLM-generated · gpt 6 astra ultra ·

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Contents
  1. Are almost all graphs determined by their spectrum?
  2. Definitions and mathematical statement
  3. Short English statement
  4. Research attempt
  5. Scope and process.
  6. Literature and chosen obstruction.
  7. A matrix proof of switching.
  8. A verified nonisomorphic pair.
  9. Why this local mechanism is rare in a random graph.
  10. Verification and exact logical gap.
  11. Final status.
  12. Sources

Are almost all graphs determined by their spectrum?

Definitions and mathematical statement

For an integer $n\geq1$, let $\mathcal G_n$ be the set of all simple undirected graphs on the labelled vertex set $[n]=\{1,\ldots,n\}$. The adjacency matrix $A_G$ has entry $1$ at $(u,v)$ precisely when $uv\in E(G)$, and has zero diagonal. Its adjacency spectrum is the multiset of its $n$ real eigenvalues, including their multiplicities. Two graphs are cospectral when these multisets agree; equivalently, their characteristic polynomials $\det(tI-A_G)$ agree.

A graph $G$ is determined by its adjacency spectrum if every finite simple graph $H$ cospectral with $G$ is isomorphic to $G$. Here an isomorphism is a bijection between the vertex sets preserving adjacency in both directions. Relabelling a graph therefore does not count as a different spectral realization. Equality of spectra already forces $|V(H)|=|V(G)|$.

The question is whether \[ \lim_{n\to\infty} \frac{|\{G\in\mathcal G_n:G\text{ is determined by its spectrum}\}|} {2^{\binom n2}}=1. \] Equivalently, choose each possible edge independently with probability $1/2$; does the probability of a nonisomorphic cospectral mate tend to zero? This specifies the usual labelled random-graph meaning of "almost all." The data supplied are only the adjacency spectrum: neither eigenvectors nor the spectrum of the complement or Laplacian is included in the reconstruction requirement.

Short English statement

Does the adjacency spectrum uniquely identify a uniformly random large graph, up to renaming its vertices, with probability tending to one?

Research attempt

Scope and process.
This is a GPT-6 Astra Ultra research attempt dated 1 October 2026, using primary-source browsing and elementary mathematical checks. The canonical definition above is retained. Results below are restricted results or reductions, not a claim of a new solution to the entire catalogue question. No formal proof assistant or external mathematical referee checked this text.
Literature and chosen obstruction.
Koval and Kwan [R1] construct exponentially many graphs determined by their adjacency spectrum, without claiming the almost-all conclusion. Abiad, Brouwer and Haemers [R2] analyze Godsil--McKay switching and the distinction between cospectrality and nonisomorphism. We check a basic switching construction explicitly, then prove that one fixed-size switching mechanism occurs with vanishing probability in $G(n,1/2)$. Eliminating one mechanism is not a proof that all spectral mates vanish.
A matrix proof of switching.
Let $X$ be a set of $k$ vertices, with $k$ even. Assume its induced graph is regular and each vertex outside $X$ has either $0$, $k/2$ or $k$ neighbours in $X$. Write the adjacency matrix in blocks as \[ A=\begin{pmatrix}B&N\\N^{\mathsf T}&D\end{pmatrix},\qquad Q=\frac2k J-I_k. \] Since $J^2=kJ$, we have $Q^2=I_k$ and $Q^{\mathsf T}=Q$. Regularity and symmetry of $B$ imply $BJ=JB=rJ$, whence $QBQ=B$. A column $v$ of $N$ of weight zero or $k$ is fixed by $Q$, and a column of weight $k/2$ is sent to ${\bf1}-v$. Thus conjugation by $\operatorname{diag}(Q,I)$ replaces each half-neighbourhood by its complement, leaves the other edges alone, and yields a simple graph adjacency matrix $A'$. It is an orthogonal similarity, so $A,A'$ have identical characteristic polynomials.
A verified nonisomorphic pair.
Take independent $X=\{1,2,3,4\}$ and independent outside vertices $a,b,c$, whose neighbourhoods in $X$ are respectively $\{1,2\},\{1,3\},\{1,4\}$. The graph is a three-armed star with each edge subdivided once. After switching, vertex $1$ is isolated and the other six vertices form a cycle. The graphs are nonisomorphic because their degree multisets are respectively \[ \{3,2,2,2,1,1,1\},\qquad\{2,2,2,2,2,2,0\}. \] The $3\times3$ matrix $N^{\mathsf T}N$ has diagonal entries two and off-diagonal entries one, so equals $I_3+J_3$ and has eigenvalues $4,1,1$. The bipartite adjacency spectrum therefore consists of $\pm2$, two copies of each of $\pm1$, and one zero. Both characteristic polynomials are $t(t^2-4)(t^2-1)^2$. The exact rational-matrix check in scripts/check_attempt_batch_algebra_2026_10_01.py also verifies the conjugation and differing degree lists.
Why this local mechanism is rare in a random graph.
Fix a particular four-vertex set $X$ in $G(n,1/2)$. For any outside vertex, its four independent adjacency bits to $X$ have allowed weights zero, two or four with probability \[ (1+6+1)/16=1/2. \] The bits for different outside vertices are independent. Therefore the probability all outside vertices satisfy the switching condition is $2^{-(n-4)}$. Requiring regularity inside $X$ can only decrease this probability. A union bound gives \[ \mathbb P(\text{some four-vertex switching set exists}) \le\binom n4\,2^{-(n-4)}\longrightarrow0. \] For a fixed even $k\ge4$, the same argument replaces $1/2$ by $\theta_k=(2+\binom k{k/2})/2^k<1$, giving the bound $\binom nk\theta_k^{n-k}\to0$. The case $k=2$ is different: $Q$ just swaps the two vertices, so this operation produces an isomorphic graph and is not a spectral ambiguity.
Verification and exact logical gap.
The nonisomorphic example proves that spectra do not determine every graph, but the conjecture concerns a probability tending to one. The probability argument concerns each fixed size $k$; it cannot be summed over unbounded $k$ without additional uniform estimates. More fundamentally, a cospectral mate need not arise from a single switching set of this form. Even ruling out all such switchings would leave other orthogonal similarities and global constructions. Adjacency cospectrality alone is used throughout; no eigenvectors, Laplacian data or spectrum of the complement have been supplied.
Final status.
UNRESOLVED. A genuine cospectral ambiguity and a rigorous vanishing-probability estimate for each fixed-size switching mechanism are established. Controlling every possible nonisomorphic cospectral mate is the first missing universal step.

Sources