CS-375 · computer science · mathematics · Quantum computing

CS-375 · Math-4564

Submultiplicativity Gaps for Stabilizer Extent

Status Partially solved · unsolvedmath.comLLM status Open unverified

Top Open Problems openaigpt 6 astra ultra 0% cataloguedPartially solvedOpen

Statement

Definitions and mathematical statement

Shared notation.
Standard number systems are denoted by $\mathbb N,\mathbb Z,\mathbb Q,\mathbb R,\mathbb C$; index ranges, computational models and specialized notation follow the cited problem source and the definitions below.

For a normalized pure $n$-qubit state $\psi$, its stabilizer extent is $\xi(\psi)=\min\{(\sum_j|c_j|)^2:\psi=\sum_jc_j\phi_j,\ \phi_j\text{ normalized stabilizer states}\}$. A stabilizer state is a common eigenstate of a maximal commuting subgroup of the qubit Pauli group. Product decompositions give $\xi(\phi\otimes\psi)\leq\xi(\phi)\xi(\psi)$. The gap may be described additively or by the ratio $\xi(\phi)\xi(\psi)/\xi(\phi\otimes\psi)$.

Statement recorded in the supplied source.
How large can the submultiplicativity gap between $\xi(\phi\otimes\psi)$ and $\xi(\phi)\xi(\psi)$ be for quantum states $\phi$ and $\psi$? [S2]
Scope qualification.
Extent is defined here for pure states, as in the source passage. The supplied question does not select an additive or multiplicative gap or fix the number of qubits; these must be stated in any quantitative bound.
Source status.
The supplied catalogue labels this record partially solved. Its source-status metadata was checked against the supplied snapshot on 2026-10-11. This import does not independently establish current open status or mathematical correctness. The catalogue literature assessment is dated 2026-08-22.

Short English statement

Quantify how much entangled stabilizer decompositions can improve on taking the product of optimal decompositions.

Sources

  • S1 Ulam AI and the UnsolvedMath Contributors, UnsolvedMath: A Curated Collection of Open Mathematics Problems, record 30004861 (OWR-8415352-003). Catalogue curation and metadata: CC BY 4.0. The supplied source question is retained; definitions and the English summary are editorial additions. https://huggingface.co/datasets/ulamai/UnsolvedMath.
  • S2 Geometry and Optimization in Quantum Information (2022), Oberwolfach Reports, DOI 10.4171/owr/2021/49, pp. 2665--2720 https://doi.org/10.4171/owr/2021/49. Underlying Oberwolfach Reports material retains its source-specific licence, including CC BY-SA 4.0 where applicable; see THIRD_PARTY_NOTICES.md.
Preparation and review.
Original question attributed to the cited source and UnsolvedMath contributors. Codex (GPT-6; exact serving revision not exposed) assisted with definitions, English summaries, source inspection and formatting. No new human mathematical authorship or independent proof verification is asserted. Canonical ID 30004861 and source code OWR-8415352-003 checked against the complete supplied registry and existing repository statements; known flagged repetitions and obvious identical conjectures excluded. Full mathematical-equivalence/literature review has not been performed. Statement preparation and final review followed contribution prompts C and D; automated checks verify structure and identity, not open status.

Catalogue entry

Statement licence: CC-BY-SA-4.0 · Source file

Contributions 1

CS-375-A1 · Exploration · LLM-generated · gpt 6 astra ultra ·

gpt 6 astra ultra attempt on CS-375

Stabilizer extent: a measurement bound and the failed amplification inference

Definitions and mathematical statement

Shared notation.
Standard number systems are denoted by $\mathbb N,\mathbb Z,\mathbb Q,\mathbb R,\mathbb C$; index ranges, computational models and specialized notation follow the cited problem source and the definitions below.

For a normalized pure $n$-qubit state $\psi$, its stabilizer extent is $\xi(\psi)=\min\{(\sum_j|c_j|)^2:\psi=\sum_jc_j\phi_j,\ \phi_j\text{ normalized stabilizer states}\}$. A stabilizer state is a common eigenstate of a maximal commuting subgroup of the qubit Pauli group. Product decompositions give $\xi(\phi\otimes\psi)\leq\xi(\phi)\xi(\psi)$. The gap may be described additively or by the ratio $\xi(\phi)\xi(\psi)/\xi(\phi\otimes\psi)$.

Statement recorded in the supplied source.
How large can the submultiplicativity gap between $\xi(\phi\otimes\psi)$ and $\xi(\phi)\xi(\psi)$ be for quantum states $\phi$ and $\psi$? [S2]
Scope qualification.
Extent is defined here for pure states, as in the source passage. The supplied question does not select an additive or multiplicative gap or fix the number of qubits; these must be stated in any quantitative bound.
Source status.
The supplied catalogue labels this record partially solved. Its source-status metadata was checked against the supplied snapshot on 2026-10-11. This import does not independently establish current open status or mathematical correctness. The catalogue literature assessment is dated 2026-08-22.

Short English statement

Quantify how much entangled stabilizer decompositions can improve on taking the product of optimal decompositions.

Sources

  • S1 Ulam AI and the UnsolvedMath Contributors, UnsolvedMath: A Curated Collection of Open Mathematics Problems, record 30004861 (OWR-8415352-003). Catalogue curation and metadata: CC BY 4.0. The supplied source question is retained; definitions and the English summary are editorial additions. https://huggingface.co/datasets/ulamai/UnsolvedMath.
  • S2 Geometry and Optimization in Quantum Information $2022$, Oberwolfach Reports, DOI 10.4171/owr/2021/49, pp. 2665--2720 https://doi.org/10.4171/owr/2021/49. Underlying Oberwolfach Reports material retains its source-specific licence, including CC BY-SA 4.0 where applicable; see THIRD_PARTY_NOTICES.md.

Verbatim supplied catalogue question

How large can the submultiplicativity gap between $\xi(\phi\otimes\psi)$ and $\xi(\phi)\xi(\psi)$ be for quantum states $\phi$ and $\psi$?

Source target and provenance of this attempt

The primary report, printed pages 2680--2682, already establishes strict submultiplicativity through the cited published paper and then asks how large the gap can be. Its duplicated factor in one printed line is interpreted as the product of the two extents, consistent with the preceding definitions and the preserved catalogue question. We treat normalized pure states and state both multiplicative and additive upper bounds as functions of the two qubit counts. These are auxiliary bounds with no sharpness or novelty claim. The root Codex GPT-6 model (exact serving revision not exposed) suggested the measurement-branch proof in its local auxiliary note. The drafting model audited that argument and supplies the complete stabilizer-closure proof below. This is additional model mathematical contribution, not human authorship or independent human verification.

Atomic norm and the measurement closure lemma

For an arbitrary vector $v$ on $n$ qubits define \[ a_n(v)=\inf\left\{\sum_j|c_j|:v=\sum_j c_jS_j, \ S_j\text{ normalized stabilizer states}\right\}. \] The computational basis makes the feasible set nonempty. The triangle inequality for the Euclidean norm and then Cauchy--Schwarz in a computational-basis expansion give \[ \|v\|_2\le a_n(v)\le2^{n/2}\|v\|_2. \] Combining expansions proves the triangle inequality; scaling coefficients and then scaling back proves $a_n(zv)=|z|a_n(v)$. For normalized $v$, $a_n(v)^2=\xi(v)$. Taking infima suffices throughout, so attainment is not needed.

We will use the following closure fact: measuring any subset of qubits of a normalized stabilizer state in the computational basis leaves, on every nonzero branch, a scalar times a normalized stabilizer state on the other qubits. Here is a full algebraic proof. An $N$-qubit stabilizer state has a group $G$ of $2^N$ commuting Hermitian Pauli operators fixing it and not containing $-I$. The average $2^{-N}\sum_{g\in G}g$ is a projector: squaring it counts each group element $2^N$ times, and it is Hermitian. Its trace is one because only $I$ has nonzero trace. Thus its range is the one-dimensional stabilized space. The same argument shows that a commuting Pauli group of size $2^{N+1}$ with no $-I$ on $N$ qubits is impossible, because its average would be a projector of trace $1/2$.

Measure the Pauli $Z$ of one qubit. If $Z$ or $-Z$ belongs to $G$, the outcome is deterministic. Otherwise some generator anticommutes with $Z$: if all commuted, adjoining $Z$ would give the impossible larger group just described. Choose such a generator $g_1$. By multiplying any other anticommuting generator by $g_1$, take the remaining $N-1$ independent generators to commute with $Z$. For either outcome sign $z\in\{-1,1\}$, replace $g_1$ by $zZ$. These $N$ generators are independent: a relation involving $Z$ would place $\pm Z$ in $G$, and a relation without it contradicts the original independence. They commute. The projected vector is nonzero because $\langle Z\rangle=\langle g_1Zg_1\rangle=-\langle Z\rangle=0$, so each outcome has probability $1/2$, and the new generators fix that vector. Thus they cannot generate $-I$.

In either case choose $zZ$ as one generator. Every other generator commutes with $Z$ and hence has only $I$ or $Z$ on this qubit; multiplying by $zZ$ removes any $Z$ there. Restricting these $N-1$ independent generators to the remaining qubits preserves independence and the absence of $-I$. Their unique stabilized vector is the residual state. The measured qubit is fixed to its computational basis outcome. Iterating proves the stated closure lemma. For a normalized joint stabilizer $S_j$, write its branch vectors as $\alpha_{jx}s_{jx}$; orthogonality of measurement outcomes gives $\sum_x|\alpha_{jx}|^2=1$.

A complete non-sharp bound on both gap conventions

Let $\phi,\psi$ be normalized $n$- and $m$-qubit states. Product expansions into stabilizers are stabilizer expansions, since the tensor products of the two independent generator groups have the required number of commuting independent generators. Taking infima proves the usual upper bound. For the lower bound, start with any joint expansion \[ \phi\otimes\psi=\sum_j c_jS_j. \] Measure the last $m$ qubits. The outcome $x$ gives $\psi_x\phi=\sum_jc_j\alpha_{jx}s_{jx}$, so \[ |\psi_x|a_n(\phi)\le\sum_j|c_j||\alpha_{jx}|. \] Square and sum over outcomes. Normalization of $\psi$ and Cauchy--Schwarz for each pair of branch-amplitude vectors imply \[ \xi(\phi)\le \sum_{i,j}|c_ic_j|\sum_x|\alpha_{ix}||\alpha_{jx}| \le\left(\sum_j|c_j|\right)^2. \] Infimize and exchange the factors to obtain \[ \max\{\xi(\phi),\xi(\psi)\} \le\xi(\phi\otimes\psi)\le\xi(\phi)\xi(\psi). \] The norm bounds above give $1\le\xi(\phi)\le2^n$ and $1\le\xi(\psi)\le2^m$. Consequently the multiplicative ratio and additive difference satisfy \[ 1\le\frac{\xi(\phi)\xi(\psi)}{\xi(\phi\otimes\psi)} \le\min\{\xi(\phi),\xi(\psi)\}\le2^{\min(n,m)}, \] \[ 0\le\xi(\phi)\xi(\psi)-\xi(\phi\otimes\psi) \le2^{n+m}-2^{\max(n,m)}. \] For the last inequality, $ab-\max(a,b)$ is nondecreasing in each variable for $a,b\ge1$: on either side of $a=b$ its slope in either variable is either the other variable or the other variable minus one. Substitute $a\le2^n,b\le2^m$. If one factor is a stabilizer, its extent is one by the one-term expansion and the norm lower bound, so the two-sided inequality proves exact equality of the product extent with the other extent. The statements include a zero-qubit scalar factor, with extent one.

Why a strict example does not amplify automatically

A natural attempted route to a large gap takes tensor powers of a known strictly submultiplicative pair. Write \[ A_t=\xi(\phi^{\otimes t}),\quad B_t=\xi(\psi^{\otimes t}),\quad C_t=\xi((\phi\otimes\psi)^{\otimes t}). \] Submultiplicativity gives $A_t\le A_1^t$, $B_t\le B_1^t$ and $C_t\le C_1^t$. The numerator estimates are upper bounds, so they do not imply $A_tB_t/C_t\ge(A_1B_1/C_1)^t$. For an exact check of the logical failure, the abstract constant sequences $A_t=B_t=2$, $C_t=3$ obey all these submultiplicative inequalities, monotonicity in $t$, and $\max(A_t,B_t)\le C_t\le A_tB_t$, but their ratio is always $4/3$. These sequences are not claimed to be realized by states; they show that the displayed inequalities alone do not amplify a strict gap. Additional control of the factor tensor powers or an explicit growing family is missing.

Adversarial audit and remaining target

The audit checked independence of replacement generators, postselection normalization, the absolute values in the branch Cauchy--Schwarz step, infima versus attained decompositions, and the direction of all tensor-power inequalities. Arbitrary partial inner products with magic states were not assumed to preserve stabilizers. The known existence of strict inequality and the source's low-qubit multiplicativity statements are context, not re-proved or counted as new progress. No numerical experiment or theorem prover was used. The sharp extremal or asymptotic gap remains unresolved by this attempt.

Process and contributions

Mathematics and model-assisted adversarial self-audit: OpenAI gpt-6-astra, ultra reasoning, as dispatched for this research batch; exact serving revision not exposed. Codex (GPT-6; exact serving revision not exposed) materially assisted with orchestration and format review. No human mathematical authorship, mathematical edits, or independent human proof checking is asserted. The coordinating Codex (GPT-6; exact serving revision not exposed) also provided a separate model-assisted written-proof review of this manuscript. This is not independent human verification. Contribution prompt A was applied to the full definition and supplied source row, then prompt B was applied adversarially to the derived results. The item-specific audit above records the scope checks and rejected extrapolations. Local assembly and structural checks do not establish mathematical correctness. The source catalogue status is preserved in TOP_PROBLEM and is separate from this attempt status.
Integration review.
Codex (GPT-6; exact serving revision not exposed) reviewed the written arguments and expanded layout and source-reference wrappers. Repository metadata and the production web renderer were checked using Python 3.13 and JavaScript with MathJax 3.2.2. This model-assisted review is not independent human proof verification; no PDF compilation or formal proof checking is asserted.

Completion Estimate

COMPLETION: 0% The proved material is a rederivation of known or auxiliary facts rather than a substantiated new advance on the original target. No sharp upper bound, matching family, or asymptotic extremal growth is obtained. The measurement bound is a known-style auxiliary estimate; tensor-power amplification lacks lower bounds for factor extents.

References

The complete original Sources subsection above is retained, including catalogue attribution and licence notices. The additional list records primary sources actually consulted for this attempt on 11 October 2026; uncited source links reproduced above were not all rechecked.
  • OWR49/2021, Geometry and Optimization in Quantum Information; primary source passages read from cached report, with precise pages identified in each manuscript. https://doi.org/10.4171/owr/2021/49.
  • Heimendahl, Montealegre-Mora, Vallentin and Gross, Stabilizer extent is not multiplicative, Quantum5,400$2021$; primary publication abstract inspected for established context, not used as an external proof dependency. https://doi.org/10.22331/q-2021-02-24-400.

Final status

Unresolved in this attempt. No sharp upper bound, matching family, or asymptotic extremal growth is obtained. The measurement bound is a known-style auxiliary estimate; tensor-power amplification lacks lower bounds for factor extents.

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