Subgroup formed by elements of order dividing n
Status Open · unsolvedmath.comLLM status Open unverified
Top Open Problems Not reported cataloguedOpenOpenStatement
Definitions and mathematical statement
Shared notation.
$\mathbb N=\{1,2,\ldots\}$, and $\mathbb Z,\mathbb Q,\mathbb R,\mathbb C$ denote the integers, rationals, reals and complex numbers. Any other conventions are specified locally.Let $G$ be a finite group with identity $1$, and let $n\geq1$ divide its order $|G|$. Define $S_n(G)=\{x\in G:x^n=1\}$, the set of elements whose orders divide $n$. A subgroup is a subset containing $1$ and closed under multiplication and inversion; a characteristic subgroup is preserved by every automorphism of $G$.
Statement recorded in the supplied source.
If $|S_n(G)|=n$, must $S_n(G)$ be a subgroup of $G$? If it is a subgroup, it is automatically characteristic, because its defining equation is invariant under every automorphism. [S2]Short English statement
Does having exactly n elements whose orders divide n force those elements to form a subgroup, whenever n divides the finite group order?Sources
- S1 ULAM.AI and the UnsolvedMath Contributors, UnsolvedMath: A Curated Collection of Open Mathematics Problems, record 3330 (OPG-732). CC BY 4.0. https://huggingface.co/datasets/ulamai/UnsolvedMath.
- S2 Open Problem Garden, Subgroup formed by elements of order dividing n, node 732, original problem page. Original question and full discussion. https://www.openproblemgarden.org/op/subgroup_formed_by_elements_of_order_dividing_n.
Statement licence: CC-BY-4.0 · Source file
Contributions 0
No attempts yet. Significant partial results and substantial reductions are welcome. Contribute an attempt.