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Math-2015

Some Questions — Question 49

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Statement

Definitions and mathematical statement

Let $p$ be a prime and $P$ a finite $p$-group, so its order $N=|P|$ is a power of $p$. A group word in $k\geq1$ variables is an element $w$ of the free group $F_k=\langle x_1,\ldots,x_k\rangle$. Substitution gives a word map \[ w_P:P^k\longrightarrow P,\qquad (g_1,\ldots,g_k)\longmapsto w(g_1,\ldots,g_k). \] Choose the $g_i$ independently and uniformly from $P$. Is it always true that \[ \Pr(w_P(g_1,\ldots,g_k)=1)\geq\frac1{|P|}, \qquad\text{equivalently}\qquad |w_P^{-1}(1)|\geq |P|^{k-1}? \] The identity element is the specified target. Requiring the same lower bound for every nonempty fiber would be the stronger Amit--Ashurst formulation; this entry retains the identity-fiber question in the source. The probability is the counting measure of the fiber divided by $N^k$.

Variables may repeat, inverses are allowed, and the word is not required to be a commutator or a power word. The tuple of identities always gives one solution, but for $k>1$ the assertion demands many more solutions. The trivial word and trivial group satisfy the inequality automatically. Both the group and the word may vary, while the proposed lower bound depends only on the group order, not on word length or the number of occurrences of a variable.

Short English statement

Does every word equation in a finite p-group have identity probability at least the reciprocal of the group order?

Sources

Catalogue entry

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