Math-554 · mathematics · Number theory

Math-554

Residue Class Multiple Coverage

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Statement

Definitions and mathematical statement

Shared notation.
Unless a section says otherwise, ${\mathbb{N}}=\{1,2,\ldots\}$, ${\mathbb{Z}}$ is the ring of integers, ${\mathbb{Q}},{\mathbb{R}},{\mathbb{C}}$ are the rational, real, and complex fields, $[N]=\{1,\ldots,\lfloor N\rfloor\}$, and $\log$ is the natural logarithm. For real functions of a parameter tending to infinity, $f\ll g$ and $f=O(g)$ mean $|f|\leq Cg$ eventually for some fixed $C$; $f\gg g$ reverses this comparison; $f=o(g)$ means $f/g\to0$; $f\sim g$ means $f/g\to1$; and $f\asymp g$ means both order bounds. A subscript on $O$ or $\ll$ specifies allowed constant dependence. The expression $n^{o(1)}$ in an upper bound means growth smaller than $n^\epsilon$ for each fixed $\epsilon>0$. Local definitions govern any exception, finite-field convention, or use of the same symbol for another object. An asymptotic claim is not automatically an effective algorithm.

For each prime $p\leq N$ choose one residue $a_p\in{\mathbb{Z}}/p{\mathbb{Z}}$. The coverage multiplicity of $m\in[N]$ is $c(m)=\#\{p\leq N:p\text{ prime},\ m\equiv a_p\pmod p\}$. The question is whether, for all sufficiently large $N$, a choice can achieve $\min_{m\in[N]}c(m)\geq10$. Different primes, not repeated use of a congruence, contribute to this count. [S1] [S2]

Statement recorded in the supplied source.
Can we pick residue classes $a_p \pmod p$, one for each prime $p \leq N$, such that every integer $\leq N$ lies in at least 10 of them? [S1]

Short English statement

Can one residue class for each available prime be chosen so that every integer in the initial interval is covered at least ten times?

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