Math-1490 · mathematics · Graph theory

Math-1490

O6 — Factoring a positive-density set of integers

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Statement

Definitions and mathematical statement

For $S\subseteq\mathbb N=\{1,2,\ldots\}$, define its lower asymptotic density by \[ \underline d(S)=\liminf_{X\to\infty}\frac{|S\cap\{1,\ldots,\lfloor X\rfloor\}|}{\lfloor X\rfloor}. \] Thus positive lower density requires a positive proportion of all sufficiently long initial intervals, not merely infinitely many easily factored integers.

Does there exist a set $S$ with $\underline d(S)>0$, together with a deterministic algorithm and a fixed polynomial $P$, such that the complete prime factorization of every $N\in S$ is produced within $P(\ell(N))$ bit operations? Here $\ell(N)$ is binary length, and complete factorization means all distinct prime factors with their multiplicities. The factorization of $1$ is the empty list.

Equivalently, one may seek a polynomial-time algorithm on all positive inputs that outputs either a verified complete factorization or a failure symbol, and whose set of successful inputs has positive lower density. To pass from the promised-set formulation to this version, run the algorithm for its polynomial time bound and check any proposed factorization; the converse uses its success set as $S$.

No efficient membership test for $S$ is required separately. The polynomial and the algorithm must be fixed uniformly, while the set $S$ may be chosen as part of a positive answer. A result restricted to a set of density zero does not establish the requested conclusion.

Short English statement

Can a deterministic polynomial-time algorithm completely factor a set of integers having positive lower density?

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