Math-2079 · mathematics · Combinatorics

Math-2079

Maximum weakly stable matchings in graphs without odd preference cycles

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Statement

Definitions and mathematical statement

Let $G=(V,E)$ be a finite simple graph. Each vertex has a complete weak order on its neighbors, permitting ties; every listed neighbor is preferred to remaining unmatched. Write $u\succ_v w$ when $v$ strictly prefers $u$ to $w$.

For each odd simple cycle $v_0v_1\cdots v_{2r}v_0$, with indices read cyclically, assume that some vertex strictly prefers its successor to its predecessor and another strictly prefers its predecessor to its successor. Ties alone do not witness either requirement.

A matching $M$ is weakly stable if there is no edge $uv\notin M$ such that both endpoints strictly prefer one another to their partners in $M$, with an unmatched endpoint treating any neighbor as preferable. Let \[ \operatorname{OPT}(G,\succ)=\max\{|M|:M\text{ is weakly stable}\}. \] The cycle hypothesis guarantees existence of a weakly stable matching. Determine how well this maximum can be approximated in polynomial time. An approximation factor $\alpha\ge1$ means an algorithm always produces a weakly stable $M$ with $|M|\ge\operatorname{OPT}/\alpha$.

Seek the best factor for this whole class and, separately, its dependence on a bound on the size of ties in individual lists. The graph need not be bipartite. Ignoring ties or replacing weak stability by strong or super-stability changes the feasible set. In particular, producing a stable matching of arbitrary size does not settle the maximum-size approximation question.

Short English statement

How closely can polynomial-time algorithms approximate the largest weakly stable matching under the stated prohibition on odd preference cycles?

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