Math-6389 · mathematics · Group theory

Math-6389

Kourovka Notebook Problem 20.124

Status Open · unsolvedmath.comLLM status Open unverified

Top Open Problems Not reported cataloguedOpenOpen

Statement

Definitions and mathematical statement

Let $F$ be a non-abelian free group. The supplied record imposes no restriction on its rank or finite generation. Define its derived subgroup by \[ [F,F]=\langle x^{-1}y^{-1}xy : x,y\in F\rangle. \] A Rota--Baxter operator on $F$ is a mapping $B:F\to F$ satisfying \[ B(g)B(h)=B\left(gB(g)hB(g)^{-1}\right) \qquad\text{for all }g,h\in F. \] The question is whether there exists such an operator with \[ \operatorname{im}(B)=\{B(g):g\in F\}=[F,F]. \] Here $F$ is an arbitrary non-abelian free group, as in the supplied formulation; no particular rank is specified.

Short English statement

Given a non-abelian free group $F$, does there exist a Rota--Baxter operator whose image is exactly the derived subgroup $[F,F]$? The supplied registry labels this problem open.

Sources

  • Local UnsolvedMath registry, permanent ID $701782$, source code catalogue entry, title Kourovka Notebook Problem 20.124. The supplied record labels the problem open.
  • Attributed in the supplied record to V. G. Bardakov, proposed in 2022.
  • Supplied source attribution: The Kourovka Notebook (Unsolved Problems in Group Theory), 20th issue (2022), problem 20.124; also identified with the 21st issue edition (2026), arXiv:1401.0300v48. The registry describes the collection as edited by E. I. Khukhro and V. D. Mazurov. These bibliographic details are supplied source data and have not been independently verified.

Catalogue entry

Statement licence: CC-BY-4.0 · Source file

Contributions 0

No attempts yet. Significant partial results and substantial reductions are welcome. Contribute an attempt.