Kourovka Notebook Problem 18.4
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Definitions and mathematical statement
Let $G$ be a group, with no finiteness assumption. A subgroup is cyclic if it is generated by one element; finite, infinite, and trivial cyclic subgroups are allowed. For subgroups $A,B\leq G$, define \[ ABA=\{a_1ba_2:a_1,a_2\in A,\ b\in B\}. \] Thus $G=ABA$ means that every element of $G$ has such an expression, without any uniqueness requirement. Define the derived series by \[ G^{(0)}=G,\qquad G^{(n+1)}=\langle [x,y]:x,y\in G^{(n)}\rangle, \qquad [x,y]=x^{-1}y^{-1}xy. \] The group $G$ is soluble if $G^{(n)}=\{1\}$ for some integer $n\geq0$.- (a) Is it true that, for every group $G$ and every pair of cyclic subgroups $A,B\leq G$, the equality $G=ABA$ implies that $G$ is soluble?
- (b) Is it true that, for every group $G$ and every pair of cyclic subgroups $A,B\leq G$ such that $G=ABA$ and $B=tAt^{-1}$ for some $t\in G$, the group $G$ is soluble?
Short English statement
Must every group that is a product $ABA$ of two cyclic subgroups be soluble? Ask the same question with the additional requirement that $A$ and $B$ are conjugate in the group. The supplied source reports an affirmative answer for finite groups.Sources
- Local UnsolvedMath registry, supplied complete record: permanent ID $701433$, exact source problem code
catalogue entry, title Kourovka Notebook Problem 18.4. The supplied status isopen; the record was updated on2026-10-16T14:00:00Z. - Supplied bibliographic attribution: The Kourovka Notebook (Unsolved Problems in Group Theory), 18th issue (2014), problem 18.4; also identified in the background as the 21st issue edition (2026), arXiv:1401.0300v48. The set description names E. I. Khukhro and V. D. Mazurov as editors. These bibliographic details are supplied source data and have not been independently verified here.
- Proposer metadata and background: B. Amberg, proposed in 2014. The mathematical statement separately attributes the problem to A. Rhemtulla and S. Sidki in its opening parenthesis. Both attributions are retained without assigning further roles.
- The supplied statement says that the assertion in part (a) is known for finite groups, but supplies no separate citation for that result.
Statement licence: CC-BY-4.0 · Source file
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