Math-1482 · mathematics · Topology

Math-1482

Kirby Problem 5.4

Status Open · unsolvedmath.comLLM status Open unverified

Top Open Problems Not reported cataloguedOpenOpen

Statement

Definitions and mathematical statement

Let $M$ be a Hausdorff second-countable topological manifold. Its homeomorphism group $\operatorname{Homeo}(M)$ consists of continuous bijections $M\to M$ with continuous inverses, under composition. Give it the compact-open topology: subbasic neighborhood conditions have the form $h(K)\subset U$ with $K\subset M$ compact and $U\subset M$ open. This is the usual transformation-group topology in the question.

A metrizable space $A$ is an absolute neighborhood retract (ANR, in the metrizable category) if whenever $A$ is embedded as a closed subset of any metrizable space $Z$, there is an open neighborhood $U$ of $A$ in $Z$ and a continuous retraction $r:U\to A$, meaning $r(a)=a$ for all $a\in A$. The condition must hold for every such closed embedding, not only for a preferred ambient space.

Is $\operatorname{Homeo}(M)$ an ANR for every manifold $M$? The group is regarded as a topological space for this question; the retraction need not be a homomorphism and no group structure on $Z$ is assumed.

The desired neighborhood-retraction property is stronger than merely constructing contractions of small neighborhoods of the identity. Local contractibility alone should not be substituted for the ANR condition. All homeomorphisms are included; no orientation-preserving restriction, compact-support restriction, or boundary-fixing subgroup is silently imposed.

Short English statement

Is the full homeomorphism group of every manifold, with its compact-open topology, an absolute neighborhood retract?

Sources

Catalogue entry

Statement licence: CC-BY-4.0 · Source file

Contributions 0

No attempts yet. Significant partial results and substantial reductions are welcome. Contribute an attempt.