Math-4141 · mathematics · Graph theory

Math-4141

Jacobians in abelian-threefold isogeny classes

Status Partially solved · unsolvedmath.comLLM status Open unverified

Top Open Problems Not reported cataloguedPartially solvedOpen

Statement

Definitions and mathematical statement

Shared notation.
$\mathbb N=\{1,2,\ldots\}$, and $\mathbb Z,\mathbb Q,\mathbb R,\mathbb C$ denote the integers, rationals, reals and complex numbers. Any other conventions are specified locally.

For an abelian variety $A/\mathbb F_q$, its Weil polynomial is $f_A(T)=\det(T-\operatorname{Frob}_q\mid V_\ell A)$, where $\ell$ is a prime different from the characteristic, $V_\ell A=(\varprojlim_r A[\ell^r](\overline{\mathbb F}_q))\otimes_{\mathbb Z_\ell}\mathbb Q_\ell$, and $\operatorname{Frob}_q$ is the $q$-power Frobenius. It has degree twice $\dim A$. An isogeny is a surjective homomorphism of abelian varieties with finite kernel. The Jacobian $\operatorname{Jac}(C)$ of a smooth projective geometrically connected curve $C$ is its abelian variety of degree-zero divisor classes.

Statement recorded in the supplied source.
Given a prime power $q$ and a polynomial $f\in\mathbb Z[T]$ promised to be the Weil polynomial of an isogeny class of abelian threefolds over $\mathbb F_q$, determine whether there is a smooth projective geometrically connected genus-three curve $C/\mathbb F_q$ such that $f_{\operatorname{Jac}(C)}=f$. The Jacobian must be defined over the stated base field: geometric existence, or existence only of a quadratic twist of a Jacobian, does not settle this question. [S2]

Short English statement

Decide which finite-field isogeny classes of abelian threefolds contain an actual genus-three Jacobian over that field.

Sources

Catalogue entry

Statement licence: CC-BY-4.0 · Source file

Contributions 0

No attempts yet. Significant partial results and substantial reductions are welcome. Contribute an attempt.