Math-1379 · mathematics · Graph theory

Math-1379

Infinite uniquely hamiltonian graphs

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Statement

Definitions and mathematical statement

Let $G$ be an infinite connected locally finite graph, meaning that each vertex has finite degree. A ray is a one-way infinite simple path. Two rays belong to the same end when, after deleting any finite vertex set, their tails lie in the same remaining component. The graph is one-ended if all its rays are equivalent in this sense.

The Freudenthal compactification $|G|$ adds one point for each end to the usual geometric realization of the graph by unit intervals. A neighborhood of an end contains the component carrying its rays after some finite vertex deletion, all ends carried by that component, and the adjacent open edge pieces entering it. A Hamilton circle is a subspace of $|G|$ homeomorphic to the ordinary circle $S^1$ and containing every vertex. Distinct parametrizations of the same subspace count as one circle. The graph is uniquely Hamiltonian when it has exactly one such subspace.

The first question asks whether there exist an integer $r>2$ and a one-ended locally finite $r$-regular graph that is uniquely Hamiltonian. Here $r$-regular means that every vertex has degree $r$.

The source also asks whether such a uniquely Hamiltonian graph exists without the one-end restriction but with every vertex and every end having the same finite degree $r>2$. The degree of an end is the supremum of the sizes of families of pairwise vertex-disjoint rays belonging to it. These are separate existence questions; in the second, the degree requirement applies to all ends as well as to all vertices.

Short English statement

Can an infinite regular graph of degree greater than two have a unique Hamilton circle with only one end, or with every end having the same degree as its vertices?

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