Math-1105 · mathematics · Graph theory

Math-1105

Graphs with a forbidden induced tree are chi-bounded

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Statement

Definitions and mathematical statement

All graphs here are finite, simple, and undirected. For $U\subseteq V(G)$, the induced subgraph $G[U]$ contains exactly the edges of $G$ with both ends in $U$. A tree is a connected graph with no cycle. Fix a finite tree $T$; a graph is $T$-free in the present sense when none of its induced subgraphs is isomorphic to $T$.

Write $\chi(G)$ for the minimum number of colours in a proper vertex colouring and $\omega(G)$ for the largest size of a clique, that is, a set of pairwise adjacent vertices. Set both parameters to zero for the empty graph. A graph class $\mathcal C$ is $\chi$-bounded if some function $f:\mathbb N_0\to\mathbb N_0$ satisfies $\chi(G)\le f(\omega(G))$ for every $G\in\mathcal C$.

The conjecture asks whether, for every fixed tree $T$, there exists a function $f_T$ such that \[ G\text{ has no induced copy of }T \quad\Longrightarrow\quad\chi(G)\le f_T(\omega(G)) \] for every finite graph $G$. The function may depend on $T$ but not on $|V(G)|$. Equivalently, for each tree $T$ and each integer $w\ge1$ there should be a finite bound $b(T,w)$ on the chromatic numbers of all $T$-free graphs with clique number at most $w$. No polynomial or effective bound is required. Replacing an induced copy by an arbitrary subgraph would change the problem: extra edges among the selected vertices are forbidden in the stated target.

Short English statement

Forbidding a fixed tree as an induced subgraph should bound the chromatic number whenever the clique number is bounded.

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