Math-5343 · mathematics · Logic

Math-5343

Fermat's little theorem and a bounded modular-factorial code

Status Solved · unsolvedmath.comLLM status Solved from source status

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Statement

Definitions and mathematical statement

For every prime $p$ and every integer $x$, Fermat's little theorem states \[ x^p\equiv x\pmod p, \] or equivalently $a^{p-1}\equiv1\pmod p$ when $p\nmid a$. The source asks for proofs of this theorem and a "simple" definition of $n!\bmod p$, allowing exponentiation. It sketches three routes: cyclicity of ${\mathbb{F}}_p^\times$, using the bound $|\{x\in{\mathbb{F}}_p:P(x)=0\}|\le\deg P$ for nonzero polynomials $P$; the permutation of $\{1,\ldots,p-1\}$ induced by multiplication by a nonzero residue $a$, giving \[ (p-1)!\equiv\prod_{i=1}^{p-1}(ai) \equiv a^{p-1}(p-1)!\pmod p; \] and the identity $(x+y)^p\equiv x^p+y^p\pmod p$. Cancellation in the product argument uses $p\nmid(p-1)!$. The supplied research aid reports completed versions of these arguments and further proofs using Lagrange's theorem and the orbits of length-$p$ words under cyclic rotation.

For the factorial-definition request, the aid adopts standard ${\mathbb{N}}$ with addition, multiplication, order and the binary exponentiation function. The following makes its bounded single-code formulation explicit. For $p\ge2$, define the base-$p$ digit relation by \[ \operatorname{Digit}_p(C,j,u)\ \Longleftrightarrow\ u<p\ \wedge\ \exists a\le C\ \exists b<p^j\ \left(C=ap^{j+1}+up^j+b\right). \] Then, for all $n\in{\mathbb{N}}$, $p\ge2$ and $r\in{\mathbb{N}}$, the reported definition of $r=n!\bmod p$ is \[ \begin{split} r<p\ \wedge\ \exists C<p^{n+1}\ \bigl(&\operatorname{Digit}_p(C,0,1) \wedge\operatorname{Digit}_p(C,n,r)\\ &\wedge\ \forall j<n\ \exists u<p\ \exists v<p\ \exists q\le j\ [\operatorname{Digit}_p(C,j,u)\wedge \operatorname{Digit}_p(C,j+1,v)\\ &\hspace{42mm}\wedge\ (j+1)u=v+qp]\bigr). \end{split} \] Every variable here ranges over ${\mathbb{N}}$. The code stores the residues of $0!,1!,\ldots,n!$ as its successive digits, and the quotient bound is $q\le j$. The assertion is that this bounded formula is correct and functional in standard arithmetic for every modulus $p\ge2$, including composite moduli, with the boundary case $n=0$ giving $r=1$. Primality is needed for Fermat's theorem, not for this definition. The source does not specify a weak formal theory in which correctness must be proved, a permitted quantifier class without exponentiation, or a precise complexity criterion for "simple." The bounded formula is one explicit interpretation of that request, not a claim of an existential polynomial definition or of provability in every weak arithmetic.

Short English statement

Give proofs of Fermat's little theorem and a simple definition of factorial residues. With exponentiation available, the research aid uses one bounded base-$p$ code for successive factorial residues; the definition also works for composite moduli.

Sources

  • Paola D'Aquino, Question 1 in the American Institute of Mathematics workshop Extensions of Hilbert's Tenth Problem, 21--25 March 2005, page 1 as identified in the supplied verification, https://aimath.org/WWN/hilberts10th/hilberts10th.pdf.
  • Local UnsolvedMath registry, permanent ID 20002338, source code catalogue entry, canonical location aim-logic-notes.json, notes[113], record dated 14 August 2026. Its verification reports lost exponents and damaged group and product notation in the extraction; the formulas here restore the meanings expressly described there. The original literature field is empty.
  • Supplied research attempt 1: partial result, problem status at run solved, rigor labelled proved, novelty confidence low. The single-code definition and additional proofs are machine-generated research aid, not peer reviewed, and require independent verification before citation; no separate bibliographic source is supplied for them.

Catalogue entry

Statement licence: CC-BY-4.0 · Source file

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