Erdős Problem #637
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Erdős problems openaigpt 6 astra ultra 100% cataloguedSolvedSolvedStatement
An $n$-vertex graph with $\operatorname{hom}(G)\leq C\log n$ has an induced subgraph on $\Omega_C(n)$ vertices with $\Omega_C(\sqrt n)$ distinct degrees. Here $\operatorname{hom}(G)$ is the maximum of the clique number and independence number. We reconstruct the diversity argument of Bukh and Sudakov, Induced subgraphs of Ramsey graphs with many distinct degrees, JCTB 97 $2007$, 612--619: https://people.math.ethz.ch/~sudakovb/distinct-degrees.pdf. The final random sampling uses independent vertex choices. See also https://www.erdosproblems.com/637.
Restatement from Math-5784-A1 r1, with the source manuscript’s qualifications.
Original problem on erdosproblems.com
Statement licence: CC-BY-4.0 · Source file
Contributions 1
GPT 6 Astra Ultra attempt on Math-5784
Erdős Problem 637: many distinct degrees in a Ramsey graph
Statement and claim.
An $n$-vertex graph with $\operatorname{hom}(G)\leq C\log n$ has an induced subgraph on $\Omega_C(n)$ vertices with $\Omega_C(\sqrt n)$ distinct degrees. Here $\operatorname{hom}(G)$ is the maximum of the clique number and independence number. We reconstruct the diversity argument of Bukh and Sudakov, Induced subgraphs of Ramsey graphs with many distinct degrees, JCTB 97 $2007$, 612--619: https://people.math.ethz.ch/~sudakovb/distinct-degrees.pdf. The final random sampling uses independent vertex choices. See also https://www.erdosproblems.com/637.External input.
We use the fixed-density asymptotic form of the Erdős--Szemerédi homogeneous-set theorem (Theorem 2.1 of that paper): for each fixed $d_0\in(0,1/2]$, and all sufficiently large $M$ depending on $d_0$, every graph $H$ of order $M$ and edge density at most $d_0$ satisfies \[ \operatorname{hom}(H)\geq c_0\,\frac{\log M}{d_0\log(1/d_0)} \] for an absolute positive constant $c_0$. Here $d_0$ is fixed before $M$ tends to infinity; this is not a bound uniform down to arbitrarily small actual graph densities. This is the only substantive external structural input.A large diverse induced subgraph.
Call an $M$-vertex graph $\eta$-diverse if each vertex has at most $M^{1/5}$ other vertices $y$ for which $|N(x)\mathbin{\triangle}N(y)|<\eta M$. Choose a sufficiently large integer $K=K(C)$, and set $\eta=1/K$ and $a=8^{-K}$. We show that $G$ contains an induced $\eta$-diverse graph of order at least $an$, for all sufficiently large $n$.Suppose otherwise. We recursively construct $K$ disjoint sets $S_1,\ldots,S_K$, each of size $q=\lfloor(an)^{1/5}\rfloor$, and nested induced graphs $G=H_0\supset H_1\supset\cdots\supset H_K$, with $|H_i|\geq|H_{i-1}|/8$ and $S_i\subset H_{i-1}\setminus H_i$. In $H=H_{i-1}$, failure of diversity supplies a vertex $x$ and $q$ other vertices $S_i$ whose neighbourhoods differ from that of $x$ in fewer than $\eta|H|$ places. In $B=V(H)\setminus S_i$, which has size at least $|H|/2$, either the neighbours or the non-neighbours of $x$ form a set $D$ of size at least $|B|/2$. Every vertex of $S_i$ has the corresponding adjacency type to all but at most $\eta|H|\leq4\eta|D|$ vertices of $D$. By averaging, at least half the vertices of $D$ have that type to at least a $1-8\eta$ fraction of $S_i$. Take these vertices for $H_i$.
Thus every vertex of every later $S_j$ has either at most $8\eta q$ neighbours in $S_i$, or at least $(1-8\eta)q$, with the choice depending only on $i$. Select at least $K/2$ sets having the same choice, and complement the graph if necessary. Their union $S$ has density at most \[ 8\eta+\frac{2}{K}=\frac{10}{K}. \] Also $\log|S|\geq\tfrac15\log n-O_C(1)$. Apply the external theorem with the fixed upper bound $d_0=10/K$. It gives \[ \operatorname{hom}(G)\geq \frac{c_0K}{10\log(K/10)} \left(\tfrac15\log n-O_C(1)\right)>C\log n \] if $K$ was chosen sufficiently large and then $n$ sufficiently large. This contradiction proves the diversity assertion.
Sampling and counting collisions.
Let $H$ be the diverse graph, of order $M\geq an$. Choose a random subset $W$ by retaining each vertex independently with probability $1/2$. For a pair $x,y$ with $|N_H(x)\triangle N_H(y)|\geq\eta M$, condition on retaining both vertices. Their degree difference in $H[W]$ is a signed sum of $D\geq\eta M-2$ independent fair Bernoulli variables. Replacing each negatively signed variable $X$ by $1-X$ shows that this sum is a translate of $\operatorname{Bin}(D,1/2)$. Its largest atom is at most $O(D^{-1/2})$, by the central binomial coefficient estimate. Consequently this pair has equal degrees with probability $O_\eta(M^{-1/2})$.There are at most $M^{6/5}$ exceptional ordered pairs. If $Z$ counts unordered pairs of retained vertices with equal degrees, it follows that \[ \mathbb EZ=O_\eta(M^{3/2}). \] Markov's inequality makes $Z\leq4\mathbb EZ$ with probability at least $3/4$. Since $|W|$ has mean $M/2$ and variance $M/4$, Chebyshev's inequality gives $\Pr(|W|<M/3)\leq9/M$. For sufficiently large $M$, both desired events occur together.
For such a set $W$, let the nonempty degree classes have sizes $u_1,\ldots,u_r$. Then \[ \sum_i u_i=|W|,\qquad \sum_i u_i^2=|W|+2Z=O_\eta(M^{3/2}). \] Cauchy--Schwarz gives \[ r\geq\frac{|W|^2}{|W|+2Z} =\Omega_\eta(\sqrt M)=\Omega_C(\sqrt n), \qquad |W|\geq an/3. \] This proves the requested assertion.