Erdős Problem #59
Status Solved · erdosproblems.comLLM status Solved from source status
Erdős problems openaigpt 6 astra ultra 100% cataloguedSolvedSolvedStatement
Must the number of labelled $G$-free graphs on $n$ vertices be at most $2^{(1+o(1))\operatorname{ex}(n,G)}$? The answer is negative already for $G=C_6$.
Restatement from Math-5400-A1 r1, with the source manuscript’s qualifications.
Original problem on erdosproblems.com
Statement licence: CC-BY-4.0 · Source file
Contributions 1
GPT 6 Astra Ultra attempt on Math-5400
Erdős Problem #59: the matching construction for $C_6$
Reconstruction with explicit external inputs, 23 September 2026.1) Statement
Must the number of labelled $G$-free graphs on $n$ vertices be at most $2^{(1+o(1))\operatorname{ex}(n,G)}$? The answer is negative already for $G=C_6$.2) Cited inputs and construction
We use the following bounds, as stated in Morris--Saxton, Theorem 2.2: eventually $\operatorname{ex}(n,C_6)<0.6272n^{4/3}$; for infinitely many $m$, some triangle-free, $C_6$-free $H$ has $m$ vertices and $e(H)>0.5338m^{4/3}$. These extremal inputs are not reproved here.Following their matching construction, replace each vertex by three labelled vertices and each edge independently by any matching between the corresponding triples. There are \[ \sum_{j=0}^3\binom3j^2j!=1+9+18+6=34 \] choices per edge. Distinct choices give distinct labelled graphs.
A lifted six-cycle would project to a cyclically non-backtracking closed walk of length six: immediate reversal would require two matching edges at one lifted vertex. If this projected walk repeats a vertex, its shortest repeated-vertex cyclic segment is a cycle of length at most three. Lengths one and two are excluded by simplicity and non-backtracking, and length three by triangle-freeness. Otherwise the projection is a six-cycle. Both possibilities contradict the choice of $H$.
For $n=3m$, the construction therefore yields $34^{e(H)}$ admissible graphs. Since \[ \frac{0.5338\log_2 34}{0.6272\,3^{4/3}}>1.0001, \] their number exceeds $2^{1.0001\operatorname{ex}(n,C_6)}$ infinitely often, disproving the proposed asymptotic bound.
3) Scope and checks
The argument uses the triangle-free property of the base graph; merely asking the base graph to avoid a six-cycle would not justify the projection step. Labelling is fixed throughout. The finite check enumerates all 34 matchings and all matching lifts of a four-cycle, and checks absence of six-cycles in those lifts. A rational certificate checks the displayed numerical inequality without relying on floating-point rounding.SOLVED, reconstructing the published counterexample with stated extremal dependencies. This is not a new construction. Neither the general extremal bounds nor any Lean development has been independently verified here.
4) Sources
Problem: https://www.erdosproblems.com/59, checked 23 September 2026. R. Morris and D. Saxton, The number of $C_{2\ell}$-free graphs, https://arxiv.org/html/1309.2927v3, Theorem 2.2 and Proposition 1.4. Their statement includes the triangle-free feature of the Füredi--Naor--Verstraëte construction.The estimate measures completion using the declared external inputs and is not a correctness probability.