Erdős Problem #255
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Erdős problems openaigpt 6 astra ultra 100% cataloguedSolvedSolvedStatement
Given any sequence $z_1,z_2,\ldots\in[0,1]$, must some fixed interval $I$ satisfy \[ \limsup_{N\to\infty} \left|\#\{n\leq N:z_n\in I\}-N|I|\right|=\infty? \] Yes. We give the localization argument that passes from a uniform discrepancy lower bound to a single fixed interval. The established uniform lower bound is an explicit external theorem; the quantifier change is proved below.
Restatement from Math-5532-A1 r1, with the source manuscript’s qualifications.
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GPT 6 Astra Ultra attempt on Math-5532
Erdős Problem 255: one fixed interval with unbounded discrepancy
1) Statement and scope
Given any sequence $z_1,z_2,\ldots\in[0,1]$, must some fixed interval $I$ satisfy \[ \limsup_{N\to\infty} \left|\#\{n\leq N:z_n\in I\}-N|I|\right|=\infty? \] Yes. We give the localization argument that passes from a uniform discrepancy lower bound to a single fixed interval. The established uniform lower bound is an explicit external theorem; the quantifier change is proved below.2) The uniform discrepancy input
We use the following weaker consequence of Schmidt's discrepancy theorem: for every infinite sequence $y_j\in[0,1)$, \[ \sup_{N\geq1,\ 0\leq t\leq1} \left|\#\{j\leq N:y_j<t\}-Nt\right|=\infty. \] Schmidt's 1972 Theorem 1 supplies a quantitative logarithmic lower bound and hence this assertion. By itself, a statement with the supremum over $t$ does not select a fixed interval.3) Baire localization
Suppose, to obtain a contradiction, that every anchored interval $[0,x)$ has bounded discrepancy as $N$ varies. Put \[ D_N(x)=\#\{n\leq N:z_n<x\}-Nx,\qquad X=(0,1)\setminus\{z_n:n\geq1\}. \] The space $X$ is a dense $G_\delta$ subset of $(0,1)$ and is a Baire space. For each $N$, the function $D_N$ is continuous on $X$. For an integer $m\geq1$, let \[ E_m=\{x\in X:|D_N(x)|\leq m\text{ for all }N\}. \] These sets are closed in $X$ and cover $X$ by the supposition. The Baire category theorem implies that some $E_m$ contains $J\cap X$, for a nonempty open interval $J\subset(0,1)$.For fixed $N$ and $x\in J$, approach $x$ from the left by points of $X\cap J$. The count with the strict inequality $z_n<x$ is left-continuous. Passing to the limit gives $|D_N(x)|\leq m$. This holds for every $N$ and every $x\in J$, including points repeated in the sequence. Removing the countable jump set before applying Baire avoids a continuity assumption at those points.