Erdős Problem #149
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Erdős problems openaigpt 6 astra ultragpt pro 5.2gpt pro 5.4 15%50% cataloguedOpenOpenStatement
Let $G=(V,E)$ be a finite simple graph with maximum degree $\Delta=\Delta(G)$. A set of edges $M\subseteq E$ is strongly independent if the induced subgraph on the endpoints of $M$ is a disjoint union of edges (equivalently, $M$ is an induced matching).
Let $\chi'_s(G)$ denote the minimum number of strongly independent edge-sets whose union is $E$ (equivalently, the minimum number of colors in a strong edge-coloring). The question is whether \[ \chi'_s(G)\ \le\ \frac54\,\Delta^2 \] for all graphs $G$.
Ambiguity note. For odd $\Delta$, the right-hand side is not an integer, and the sharp Erdős--Nešetřil conjecture is usually stated with a slightly smaller (still $\sim \frac54\Delta^2$) expression. Interpreting the prompt literally, one should read it as $\chi'_s(G)\le \left\lceil \frac54\Delta^2\right\rceil$.
Restatement from Math-5460-A2 r1, with the source manuscript’s qualifications.
Original problem on erdosproblems.com
Statement licence: CC-BY-4.0 · Source file
Contributions 3
gpt pro 5.4 attempt on Math-5460
Erdős Problem #149 (Round 2): corrected formulation and a broad solved class
1) ROUND-2 OBJECTIVE
Here I pursue path (C): the literal Round-1 formulation \[ \chi'_s(G)\le \frac54\,\Delta^2 \] is not the standard exact Erdős--Nešetřil conjecture when $\Delta$ is odd. The minimal corrected target is \[ \chi'_s(G)\le \frac54\,\Delta^2 \qquad \mbox{if $\Delta$ is even}, \] and \[ \chi'_s(G)\le \frac{5\Delta^2-2\Delta+1}{4} \qquad \mbox{if $\Delta$ is odd}. \] My Round-2 goal is then to prove this corrected statement for a nontrivial infinite class of graphs, thereby excluding that entire class from any potential counterexample.The class I will handle is: all $2$-degenerate graphs.
2) Round-1 FOUNDATION USED
I use the following Round-1 points.- The line-graph reformulation \[ \chi'_s(G)=\chi(L(G)^2). \]
- The Round-1 greedy upper bound \[ \chi'_s(G)\le 2\Delta^2-2\Delta+1. \]
- The Round-1 $C_5$-blow-up example showing that the conjectured constant is tight in the even-$\Delta$ regime.
- The Round-1 ambiguity note that the odd-$\Delta$ case requires a piecewise correction.
3) NEW INSIGHT / TOOL (ROUND 2)
The new ingredient is to combine two known theorems that were not used in Round 1.- Andersen's theorem. Every graph with maximum degree at most $3$ has strong chromatic index at most $10$.
- Yu's theorem for $k$-degenerate graphs. Every $k$-degenerate graph of maximum degree $\Delta$ satisfies \[ \chi'_s(G)\le (4k-2)\Delta-k(2k-1)+1. \] For $k=2$, this becomes \[ \chi'_s(G)\le 6\Delta-5. \]
These two statements together imply that the corrected Erdős--Nešetřil bound holds for every $2$-degenerate graph.
4) ATTACK PLAN (ROUND 2)
Round 1 left a huge gap between the general greedy bound and the conjectured piecewise bound. I will not close that general gap, but I will prove a broad solved class.The exact claims to prove are:
- If $G$ is $2$-degenerate and $\Delta\ge 4$, then Yu's theorem gives a linear bound $6\Delta-5$, and this linear bound is already at most the corrected Erdős--Nešetřil target.
- If $G$ is $2$-degenerate and $\Delta\le 3$, then the corrected target also holds: for $\Delta\le 2$ this follows from the Round-1 greedy bound, and for $\Delta=3$ it follows from Andersen's theorem.
This will prove the conjectured bound for all $2$-degenerate graphs and hence show that any counterexample must have degeneracy at least $3$ (and in particular maximum degree at least $4$).
5) WORK (ROUND 2)
External theorem 1 (Andersen).
If $G$ is a graph with maximum degree at most $3$, then \[ \chi'_s(G)\le 10. \]External theorem 2 (Yu).
If $G$ is a $k$-degenerate graph with maximum degree $\Delta$, then \[ \chi'_s(G)\le (4k-2)\Delta-k(2k-1)+1. \] In particular, if $G$ is $2$-degenerate, then \[ \chi'_s(G)\le 6\Delta-5. \]Claim.
Every $2$-degenerate graph satisfies the corrected Erdős--Nešetřil bound \[ \chi'_s(G)\le \frac54\,\Delta^2 \qquad \mbox{if $\Delta$ is even}, \] and \[ \chi'_s(G)\le \frac{5\Delta^2-2\Delta+1}{4} \qquad \mbox{if $\Delta$ is odd}. \]Proof.
Let $G$ be $2$-degenerate, and let $\Delta=\Delta(G)$.Case 1: $\Delta\le 2$. By the Round-1 greedy bound, \[ \chi'_s(G)\le 2\Delta^2-2\Delta+1. \] For $\Delta=1$, this is $1$, which equals the corrected target. For $\Delta=2$, this is $5$, which again equals the corrected target \[ \frac54\cdot 2^2=5. \]
Case 2: $\Delta=3$. By Andersen's theorem, \[ \chi'_s(G)\le 10. \] The corrected odd-$\Delta$ target equals \[ \frac{5\Delta^2-2\Delta+1}{4} = \frac{45-6+1}{4} =10. \] So the target holds exactly.
Case 3: $\Delta\ge 4$ and even. By Yu's theorem, \[ \chi'_s(G)\le 6\Delta-5. \] So it is enough to check \[ 6\Delta-5\le \frac54\,\Delta^2. \] This is equivalent to \[ 5\Delta^2-24\Delta+20\ge 0. \] The quadratic function on the left has derivative $10\Delta-24>0$ for every $\Delta\ge 3$, so it is increasing on $[4,\infty)$. At $\Delta=4$ it equals \[ 5\cdot 16-24\cdot 4+20=4>0. \] Hence it is positive for every even $\Delta\ge 4$, proving the desired inequality.
Case 4: $\Delta\ge 5$ and odd. Again Yu gives \[ \chi'_s(G)\le 6\Delta-5. \] Now it is enough to check \[ 6\Delta-5\le \frac{5\Delta^2-2\Delta+1}{4}. \] This is equivalent to \[ 5\Delta^2-26\Delta+21\ge 0. \] Its derivative is $10\Delta-26>0$ for every $\Delta\ge 3$, so it is increasing on $[5,\infty)$. At $\Delta=5$ it equals \[ 5\cdot 25-26\cdot 5+21=16>0. \] Hence it is positive for every odd $\Delta\ge 5$.
All cases are proved.
Corollary.
Any counterexample to the corrected Erdős--Nešetřil conjecture must have degeneracy at least $3$ and maximum degree at least $4$.Proof.
If the graph had degeneracy at most $2$, the claim above would dispose of it. If it had maximum degree at most $3$, Cases 1 and 2 would dispose of it. Therefore every counterexample lies outside both ranges.6) ADVERSARIAL VERIFICATION
I check the delicate points.- Odd-$\Delta$ correction. The corrected target is the standard piecewise Erdős--Nešetřil form, not simply $\lceil 5\Delta^2/4\rceil$. This matters already at $\Delta=3$, where the exact target is $10$.
- Small degrees. Yu's linear estimate is not enough for $\Delta=3$, since it gives $13$. That is why Andersen's theorem is required in Case 2.
- Use of Round-1 results. The Round-1 greedy bound is only used for $\Delta\le 2$, where it is exact enough. There is no hidden dependence on unproved new claims.
- Hypotheses of external theorems. Yu requires only $k$-degeneracy and maximum degree; Andersen requires only $\Delta\le 3$. These hypotheses are exactly what is used here.
7) FINAL
UNRESOLVED (BUT STRICTLY ADVANCED).Round 2 does not solve the corrected Erdős--Nešetřil conjecture in full, but it gives a real structural advance over Round 1:
- it replaces the vague odd-$\Delta$ formulation by the standard exact piecewise conjecture;
- it proves that the corrected conjecture holds for every $2$-degenerate graph;
- consequently, it rules out all $2$-degenerate graphs from the search for a counterexample.
8) COMPLETION ESTIMATE
COMPLETION: 50%9) REFERENCES
- Erdős Problems, Problem #149, checked on 7 March 2026.
- Lars Døvling Andersen, The strong chromatic index of a cubic graph is at most 10, Discrete Mathematics 108 $1992$, 231--252.
- Gexin Yu, Strong edge-colorings for $k$-degenerate graphs, Graphs and Combinatorics 31 $2015$, 1815--1818; see also arXiv:1212.6093.
GPT 6 Astra Ultra attempt on Math-5460
Problem 149: a degeneracy threshold beyond the supplied subclass
1) OBJECTIVE AND SOURCE REVIEW
Attempt dated 2026-09-23. The strong chromatic index conjecture asks for at most $5\Delta^2/4$ colors for even $\Delta$, and $(5\Delta^2-2\Delta+1)/4$ for odd $\Delta$. I readgpt_pro_5.4/149.tex fully. It applies Yu's theorem to 2-degenerate graphs. I retain the general degeneracy parameter to obtain a wider certified region. 2) WORK
The checked theorem of Yu states that a $k$-degenerate graph has strong chromatic index at most \[ U(k,\Delta)=(4k-2)\Delta-k(2k-1)+1. \] This is a published input. Let $k\ge1$ and suppose $k\le5\Delta/16$. Then \[ U(k,\Delta)\le\frac54\Delta^2-2\Delta-2k^2+k+1 \le\frac54\Delta^2-2\Delta. \] The last step uses $-2k^2+k+1\le0$. This is below both parity-dependent conjectured bounds for $\Delta\ge1$. Thus every graph with degeneracy at most $5\Delta/16$ satisfies the conjecture. In particular, a counterexample must have degeneracy strictly greater than $5\Delta/16$, in addition to the restrictions in the supplied attempt.Keeping the constant term gives a better small example: for $k=3$, $U=10\Delta-14$. For even $\Delta\ge8$, the difference from the target, multiplied by 4, is $5\Delta^2-40\Delta+56>0$; it is 56 at 8 and increasing. For odd $\Delta\ge7$ the corresponding difference is $5\Delta^2-42\Delta+57>0$; it is 8 at 7 and increasing. Therefore all 3-degenerate graphs with $\Delta\ge7$ are also certified, even where the simpler ratio threshold does not apply.
3) ADVERSARIAL VERIFICATION
The odd target is smaller than $5\Delta^2/4$, so it must be checked separately; the displayed inequalities do so. Degree zero is immediate, with no edges to color. Degeneracy three alone does not settle the intermediate maximum degrees 4, 5, and 6 through this estimate: substituting the bound does not justify those cases. These are corollaries of an existing theorem, not new universal coloring algorithms.4) FINAL
UNRESOLVED. The unsolved regime still includes graphs with degeneracy comparable to their maximum degree, including the extremal constructions. No bound for that whole regime is proved here.5) SOURCES CHECKED
Complete supplied file; G. Yu, Strong edge-colorings for $k$-degenerate graphs,https://arxiv.org/abs/1212.6093, checked 2026-09-23 for the exact formula. 6) COMPLETION ESTIMATE
Subjective progress toward the universal conjecture. COMPLETION: 15%gpt pro 5.2 attempt on Math-5460
Erdős Problem #149: Strong chromatic index
FORMAL RESTATEMENT
Let $G=(V,E)$ be a finite simple graph with maximum degree $\Delta=\Delta(G)$. A set of edges $M\subseteq E$ is strongly independent if the induced subgraph on the endpoints of $M$ is a disjoint union of edges (equivalently, $M$ is an induced matching).Let $\chi'_s(G)$ denote the minimum number of strongly independent edge-sets whose union is $E$ (equivalently, the minimum number of colors in a strong edge-coloring). The question is whether \[ \chi'_s(G)\ \le\ \frac54\,\Delta^2 \] for all graphs $G$.
Ambiguity note. For odd $\Delta$, the right-hand side is not an integer, and the sharp Erdős--Nešetřil conjecture is usually stated with a slightly smaller (still $\sim \frac54\Delta^2$) expression. Interpreting the prompt literally, one should read it as $\chi'_s(G)\le \left\lceil \frac54\Delta^2\right\rceil$.
QUICK LITERATURE/CONTEXT CHECK
This is the classical Erdős--Nešetřil conjecture $1985$. It is known that the constant $5/4$ would be best possible via a blow-up construction of $C_5$. The best general asymptotic upper bound currently recorded in the Erdős Problems database is $\chi'_s(G)\le 1.772\,\Delta^2$ for sufficiently large $\Delta$ (Hurley--de Joannis de Verclos--Kang), improving earlier constants $1.835,1.93,1.998$.It also remains open in full generality whether the clique number of $L(G)^2$ is at most $\frac54\Delta^2$, although it is known under additional forbidden-cycle hypotheses.
DEFINITIONS / SETUP
- Strong edge-coloring. A map $\varphi:E\to [t]$ is a strong edge-coloring if whenever $e\neq f$ have $\varphi(e)=\varphi(f)$, then $e$ and $f$ are strongly independent (i.e. form an induced matching).
- Strong chromatic index. $\chi'_s(G)$ is the minimum $t$ for which a strong edge-coloring exists.
- Line graph formulation. Let $L(G)$ be the line graph of $G$ and $L(G)^2$ its square. Then $\chi'_s(G)=\chi(L(G)^2)$: edges of $G$ are vertices of $L(G)$, and "strong conflict" corresponds to distance at most $2$ in $L(G)$.
KNOWN RESULTS I WILL USE
I only use two elementary facts, each proved below: a greedy upper bound and the blow-up lower bound.MAIN ATTEMPT
1) Elementary greedy upper bound $\chi'_s(G)\le 2\Delta^2-2\Delta+1$
Count the number of edges at strong distance at most $1$ from $e$: there are at most $(\deg(u)-1)+(\deg(v)-1)\le 2(\Delta-1)$ edges incident to $u$ or $v$ other than $e$.
Now consider edges at strong distance exactly $2$ from $e$. Any such edge must be incident to a neighbor of $u$ or of $v$ (other than $u,v$ themselves). The vertex $u$ has at most $\Delta-1$ neighbors besides $v$, and each such neighbor $w$ is incident to at most $\Delta-1$ edges other than $uw$. Thus the number of edges incident to the neighbors of $u$ (excluding those already counted as incident to $u$) is at most $(\Delta-1)(\Delta-1)=(\Delta-1)^2$. Similarly for $v$, giving at most $2(\Delta-1)^2$ additional forbidden edges.
Hence, at the time we color $e$, there are at most \[ 2(\Delta-1) + 2(\Delta-1)^2 = 2\Delta^2-2\Delta \] previously colored edges whose colors cannot be used. Therefore at most $2\Delta^2-2\Delta$ colors are forbidden, so with $2\Delta^2-2\Delta+1$ colors available, a greedy choice always succeeds. ∎
2) The blow-up of $C_5$ yields the lower bound $5\Delta^2/4$
It remains to show that in $G$ no two distinct edges are strongly independent, i.e. every color class in a strong edge-coloring has size at most $1$. Let $e\neq f$ be edges of $G$. Project each edge to the corresponding base edge of $C_5$ (i.e. remember only which pair of parts it lies between). In $C_5$, any two distinct edges are at distance at most $2$ in the line graph (indeed $L(C_5)\cong C_5$ and $L(C_5)^2\cong K_5$). Translating back to $G$, this implies that for any two edges $e,f$ there is either
- a shared endpoint (if the corresponding base edges share a vertex), or
- an adjacency between an endpoint of $e$ and an endpoint of $f$ coming from a base edge connecting the relevant parts (if the base edges are at line-graph distance $2$).
ADVERSARIAL CHECK
- Proposition Proposition (Greedy bound) only uses an upper bound on the number of conflicting edges; overcounting is harmless. The conclusion is therefore safe.
- Proposition prop:C5blowup hinges on the claim that any two distinct edges in the blow-up are at distance at most $2$ in the line graph. This is true because the base edges of $C_5$ already have this property, and the blow-up only adds adjacencies, never removes them.
- These arguments do not approach the conjectured constant $5/4$ from above; they only show $1$ a coarse universal bound $2\Delta^2+O(\Delta)$ and $2$ that $5/4$ would be best possible.
FINAL
UNRESOLVED --- PARTIAL PROGRESS.- Farthest point reached. I gave complete proofs of (i) the classical greedy bound $\chi'_s(G)\le 2\Delta^2-2\Delta+1$ and (ii) the $C_5$ blow-up construction showing $\chi'_s(G)$ can equal $\frac54\Delta^2$ (so the conjectured constant is tight for even $\Delta$).
- Remaining gap. Proving $\chi'_s(G)\le \frac54\Delta^2$ (or giving a counterexample) for general graphs remains open; existing best results replace $5/4$ by a larger constant (currently $\approx 1.772$).
- Promising next steps. Any improvement seems to require either (a) improved control on sparse neighborhood structure in $L(G)^2$ together with probabilistic coloring methods, or (b) structural decomposition approaches for extremal configurations resembling the $C_5$ blow-up.
COMPLETION: 30%