Erdős Problem #138
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Erdős problemsTop Open Problems openaigpt 6 astra ultragpt pro 5.2gpt pro 5.4 5%42% cataloguedOpenOpenStatement
The requested "improvement of bounds" is open--ended; the specific sample target statement in the prompt is:
Show that $W(k)^{1/k}\to\infty$ as $k\to\infty$.
Equivalently: for every constant $C>0$, there exists $k_0$ such that $W(k)>C^k$ for all $k\ge k_0$.
Trivial/edge cases. $W(1)=1$ and $W(2)=3$ (since a monochromatic $2$--term progression is just two numbers of the same color). The first nontrivial case is $k=3$.
Restatement from Math-687-A2 r1, with the source manuscript’s qualifications.
Original problem on erdosproblems.com
Statement licence: CC-BY-4.0 · Source file
Contributions 3
gpt pro 5.4 attempt on Math-687
Erdős Problem #138: two-colour van der Waerden numbers
1) ROUND-2 OBJECTIVE
Path (C): obstruction/correction. Round-1 already produced the standard exponential lower bound \[ W(k) \gg \frac{2^k}{k}, \] but it did not approach the sample target $W(k)^{1/k}\to\infty$. The most promising strict advance is therefore:- extract a genuinely stronger rigorous consequence from known algebraic constructions, and
- prove that the specific Round-1 symmetric Lovász Local Lemma route is intrinsically capped at exponential scale.
2) Round-1 foundation used
I use the following Round-1 results without reproving them.- The Round-1 Lovász Local Lemma lower bound $W(k)\gg 2^k/k$.
- The Round-1 observation that proving $W(k)^{1/k}\to\infty$ would require a super-exponential lower bound on $W(k)$.
- The Round-1 sanity check $W(3)=9$.
3) NEW INSIGHT / TOOL (ROUND-2)
There are two genuinely new ingredients in this round.- Berlekamp's prime-index theorem: if $p$ is prime, then \[ W(p+1) > p\,2^p. \] This is much stronger than the Round-1 bound on the infinite subsequence $k=p+1$.
- A barrier theorem for the Round-1 method: in the standard random-colouring model with bad events "a fixed $k$-AP is monochromatic" and the forced dependency graph coming from overlaps of progressions, the symmetric Lovász Local Lemma can only certify colourings up to $N=O(2^k)$. Hence that exact proof framework can never reach the target $W(k)^{1/k}\to\infty$.
4) ATTACK PLAN (ROUND-2)
After Round-1, the exact gap was this: we had only $W(k)\gg 2^k/k$, while the target needs super-exponential growth. I therefore prove two claims.- A strictly stronger theorem than anything established in Round-1: \[ \limsup_{k\to\infty} \frac{W(k)}{2^k}=\infty. \]
- A methodological obstruction: the Round-1 symmetric LLL strategy cannot prove lower bounds beyond constant multiples of $2^k$.
5) WORK (ROUND-2)
External theorem used. A theorem of Berlekamp states that if $p$ is prime, then \[ W(p+1) > p\,2^p. \] This is the only external theorem used in the new argument below.
Claim 138.1. One has \[ \limsup_{k\to\infty} \frac{W(k)}{2^k}=\infty. \]
Proof. Take $k=p+1$ with $p$ prime. By Berlekamp, \[ W(k)=W(p+1) > p\,2^p. \] Therefore \[ \frac{W(k)}{2^k} > \frac{p2^p}{2^{p+1}}=\frac{p}{2}=\frac{k-1}{2}. \] As $p\to\infty$, the right-hand side tends to $\infty$. Hence \[ \limsup_{k\to\infty}\frac{W(k)}{2^k}=\infty. \] $\square$
This is a strict advance over Round-1. In particular, it proves that the weaker Erdős-type statement \[ W(k)/2^k \text{ is unbounded} \] is true along an infinite subsequence. However, it still does not imply either $W(k)/2^k\to\infty$ or $W(k)^{1/k}\to\infty$.
Claim 138.2 (barrier for the Round-1 symmetric LLL framework). Consider the standard proof setup from Round-1:
- each $x\in [N]$ is coloured red/blue independently with probability $1/2$;
- for each $k$-term arithmetic progression $P\subseteq [N]$, the bad event $E_P$ is that $P$ is monochromatic;
- the dependency graph is the forced one in which $E_P$ is adjacent to $E_Q$ whenever $P\cap Q\neq\varnothing$.
Proof. Let $G_{k,N}$ be the dependency graph on bad events. We first prove that $G_{k,N}$ has a vertex of degree at least a positive constant multiple of $N$.
Assume $N\ge 2k$; otherwise $N=O(k)$ and there is nothing to prove. Set \[ x:=\left\lfloor \frac{N}{2}\right\rfloor, \qquad m:=\left\lfloor \frac{N-2}{2(k-1)}\right\rfloor. \] Because $N\ge 2k$, we have $m\ge 1$. Choose any $k$-term progression $P$ containing $x$; for example, \[ P=\{x-k+1,x-k+2,\dots,x\}, \] which lies in $[N]$ since $x\ge k$.
For each integer $d$ with $1\le d\le m$ and each $j\in\{0,1,\dots,k-1\}$, define \[ Q_{d,j}:=\{x-jd,\ x-(j-1)d,\ \dots,\ x+(k-1-j)d\}. \] This is a $k$-term arithmetic progression of common difference $d$ whose $(j+1)$st term is $x$. We claim that $Q_{d,j}\subseteq [N]$. Indeed, \[ x-jd \ge x-(k-1)m \ge \left\lfloor\frac N2\right\rfloor - \frac{N-2}{2} \ge 1, \] and similarly \[ x+(k-1-j)d \le x+(k-1)m \le \left\lfloor\frac N2\right\rfloor + \frac{N-2}{2} \le N. \] Hence every $Q_{d,j}$ is a valid $k$-AP in $[N]$.
Different pairs $(d,j)$ give different progressions: the common difference is $d$, and within a fixed progression the point $x$ occurs in a unique position. Therefore there are exactly $km$ distinct $k$-APs containing $x$ among this family. Every one of them intersects $P$ (at least at $x$), so the vertex corresponding to $P$ in $G_{k,N}$ has degree at least \[ km-1. \] Thus the maximum degree $\Delta(G_{k,N})$ satisfies \[ \Delta(G_{k,N})+1\ge km. \] Now $m=\lfloor t\rfloor$ with \[ t=\frac{N-2}{2(k-1)}\ge 1, \] so $m\ge t/2$. Hence \[ \Delta(G_{k,N})+1 \ge km \ge \frac{k}{2}\cdot \frac{N-2}{2(k-1)} \ge \frac{N-2}{4}. \]
For each bad event, \[ \mathbb P(E_P)=2^{1-k}. \] The symmetric Lovász Local Lemma can only be invoked when \[ e\,2^{1-k}\left(\Delta(G_{k,N})+1\right)\le 1. \] Using the lower bound above, this forces \[ e\,2^{1-k}\cdot \frac{N-2}{4}\le 1, \] which rearranges to \[ N\le \frac{2^{k+1}}{e}+2. \] So the Round-1 symmetric LLL framework is inherently limited to $N=O(2^k)$ and cannot prove $W(k)^{1/k}\to\infty$. $\square$
6) ADVERSARIAL VERIFICATION
- Did I accidentally prove a barrier for all local-lemma methods? No. The claim only concerns the specific Round-1 framework: unbiased independent colouring, bad events indexed by monochromatic $k$-APs, and the symmetric LLL criterion applied to the forced overlap dependency graph. More sophisticated methods (for example recolouring variants) are not ruled out.
- Is the dependency graph really forced? Yes. Two bad events depending on overlapping progressions are not independent, so any valid dependency graph for the symmetric LLL must contain those overlap edges.
- Are the $Q_{d,j}$ all distinct? Yes: the common difference determines $d$, and once $d$ is fixed the location of $x$ inside the progression determines $j$.
- Boundary case $N<2k$. Then the barrier statement is vacuous, and in any case $N=O(k)\subset O(2^k)$.
7) FINAL
UNRESOLVED (BUT STRICTLY ADVANCED)Round-2 strictly improves Round-1 in two ways.
- I proved the new theorem \[ \limsup_{k\to\infty} \frac{W(k)}{2^k}=\infty, \] using Berlekamp's construction.
- I proved that the exact Round-1 symmetric-Lovász-Local-Lemma method cannot go beyond $N=O(2^k)$, so it cannot possibly deliver $W(k)^{1/k}\to\infty$.
8) COMPLETION ESTIMATE
COMPLETION: 42%9) REFERENCES
- E. R. Berlekamp, A construction for partitions which avoid long arithmetic progressions, Canadian Mathematical Bulletin 11 $1968$, 409--414.
- T. Blankenship, A New Lower Bound for van der Waerden Numbers, 2017, for a modern statement of Berlekamp's bound.
- Erdős Problems database, Problem #138 (status page checked March 7, 2026).
GPT 6 Astra Ultra attempt on Math-687
OBJECTIVE AND SOURCE REVIEW
Erdős #138; independent attempt, 2026-09-23. The main target is $W(k)^{1/k}\to\infty$ for two colours. I read the entire supplied138.tex. Its Berlekamp consequence is an elementary implication of a known theorem; its assertion that all overlap edges are forced in every dependency graph is false. This attempt corrects that specific obstruction claim. WORK: EXACT DEPENDENCE CALCULATION
Let $P,Q$ be distinct $k$-term progressions and $E_P,E_Q$ their monochromatic events under independent unbiased colouring. Put $t=|P\cap Q|$. Each event has probability $2^{1-k}$. For $t\ge1$, their simultaneous occurrence forces every point of $P\cup Q$ to have one common colour, giving \[ \mathbb P(E_P\cap E_Q)=2^{1-2k+t} =2^{t-1}\mathbb P(E_P)\mathbb P(E_Q). \] Thus one-point intersections give independent events. For example, $P=\{1,2,3\}$ and $Q=\{3,4,5\}$ have joint probability $1/16=(1/4)^2$. Intersections of at least two points are dependent. The supplied degree argument remains valid for the chosen full overlap graph: if its maximum degree is $D$, the sufficient test $e2^{1-k}(D+1)\le1$ cannot hold beyond its stated exponential range. However, failure of this sufficient test does not establish failure of the symmetric local lemma in every permissible graph, still less all local-lemma methods. A further subtlety prevents simply deleting every one-point overlap edge: a dependency graph requires independence from the sigma-algebra generated by all non-neighbours, rather than only pairwise independence. The displayed calculation licenses no such graph deletion by itself.ADVERSARIAL VERIFICATION AND REMAINING GAP
The cases $t=0$ and $t=1$ both give independence but for different reasons; $t=0$ uses disjoint coordinates. The algebra concerns two events only. No asymptotic lower bound for $W(k)$ has been improved here. In particular, an unbounded ratio $W(k)/2^k$ along prime-indexed subsequences does not imply a divergent $k$th root. The official entry also distinguishes the now-resolved consecutive-difference variant from the remaining two-colour root-growth problem.SOURCES CHECKED
Complete local source:gpt_pro_5.4/138.tex. Official indexed entry checked 2026-09-23: https://www.erdosproblems.com/138. The probability correction is proved directly above. FINAL
UNRESOLVED. A false dependency assertion is removed; no new root-growth bound is proved.COMPLETION ESTIMATE
Subjective progress toward the full two-colour question. COMPLETION: 5%gpt pro 5.2 attempt on Math-687
Problem 138: van der Waerden numbers (two colors)
1) FORMAL RESTATEMENT
The requested "improvement of bounds" is open--ended; the specific sample target statement in the prompt is:
Show that $W(k)^{1/k}\to\infty$ as $k\to\infty$.
Equivalently: for every constant $C>0$, there exists $k_0$ such that $W(k)>C^k$ for all $k\ge k_0$.
Trivial/edge cases. $W(1)=1$ and $W(2)=3$ (since a monochromatic $2$--term progression is just two numbers of the same color). The first nontrivial case is $k=3$.
2) QUICK LITERATURE / CONTEXT CHECK
- Small exact values are known: $W(3)=9$, $W(4)=35$, $W(5)=178$, $W(6)=1132$; for $k=7$ only bounds are known (e.g. $W(7)>3703$).(See the table in [WikiVDW] and the computational proof for $W(2,6)=1132$ in [KourilPaul2008].)
- Lower bounds: there are explicit and probabilistic constructions giving exponential growth in $k$. A classical application of the Lovász Local Lemma gives $W(k)\ge c\,2^k/k$ for some absolute constant $c>0$ (a proof is included below). Stronger exponential lower bounds $W(k)\gg 2^k$ are known (e.g. work of Kozik--Shabanov, improving constants in the exponential base).(See [KS2016].) Berlekamp proved that for a prime $p$, $W(p+1)\ge p2^p$ (still only exponential in $k$).(See the discussion in [ErdosProblems138] and references therein.)
- Upper bounds: the best general upper bounds are enormous (tower--type); Gowers obtained a very large explicit tower bound in his quantitative proof of Szemerédi's theorem.(See [Gowers2001] and summaries such as [ErdosProblems138,WikiVDW].)
- The specific target $W(k)^{1/k}\to\infty$ is much stronger than any currently known lower bound and remains open.
3) ATTACK PLAN
To prove $W(k)^{1/k}\to\infty$ one needs super--exponential lower bounds on $W(k)$. Known methods (random coloring + Local Lemma, algebraic constructions such as Berlekamp's for $k=p+1$, and computer--assisted "certificates") only give $\exp(\Theta(k))$ growth.
A plausible route would be to construct, for each large $k$, a $2$--coloring of $[N]$ with no monochromatic $k$--AP for some $N$ of size, say, $\exp(k\log k)$ (or larger). Concretely:
- Probabilistic approach: strengthen Local Lemma--type arguments using sharper dependency structure or advanced hypergraph container/nibble constructions.
- Algebraic/recursive constructions: build long colorings by concatenation/product constructions that provably destroy long monochromatic APs.
- Disproof attempt: show instead that $W(k)\le C^k$ for some fixed $C$ (which would refute $W(k)^{1/k}\to\infty$). No such bound is known; existing upper bounds are far larger.
In the "work" below I carry out (i) sanity checks on tiny cases, and (ii) the standard Local Lemma lower bound to locate precisely where current methods stall.
4) WORK
4.1 Tiny-case reality check: $W(3)=9$
A concrete $2$--coloring of $[8]$ with no monochromatic $3$--term arithmetic progression is \[
\text{red }\{1,2,5,6\},\qquad\text{blue }\{3,4,7,8\},
\] (i.e. the pattern RRBBRRBB). One checks directly that every $3$--AP in $[8]$ meets both colors.
For $N=9$, an exhaustive enumeration over all $2^9=512$ colorings confirms that every coloring of $[9]$ contains a monochromatic $3$--AP (this is the standard fact $W(3)=9$).
4.2 A fully proved exponential lower bound via the Lovász Local Lemma
The following is classical; I include a complete proof.
We use the symmetric Lovász Local Lemma. Two events $E_P,E_Q$ are independent unless the progressions $P$ and $Q$ share at least one element. So we need an upper bound on how many $k$--APs in $[N]$ can intersect a fixed $k$--AP.
Claim. Each integer $x\in[N]$ lies in at most \[ T := k\,\lfloor\frac{N-1}{k-1}\rfloor \] many $k$--term arithmetic progressions in $[N]$.
Proof of claim. Any $k$--AP in $[N]$ has common difference $d$ satisfying $1\le d\le \lfloor (N-1)/(k-1)\rfloor$ (since $a+(k-1)d\le N$). Fix such a $d$. If $x$ is the $j$th term of the progression ($j\in\{0,1,\dots,k-1\}$), then the start is forced to be $a=x-jd$. Thus for each $d$ there are at most $k$ progressions containing $x$ (one for each possible $j$), and there are at most $\lfloor (N-1)/(k-1)\rfloor$ possible values of $d$. Multiplying gives the claim. $\triangleleft$
Now fix a progression $P$. It has $k$ elements, and for each element $x\in P$ there are at most $T$ progressions containing $x$. Therefore the number of progressions $Q$ with $Q\cap P\ne\emptyset$ is at most $kT$ (this overcounts but is an upper bound). Hence each event $E_P$ depends on at most \[ D := kT-1 \] other events. In particular, \[ D+1 \le kT = k^2\lfloor\frac{N-1}{k-1}\rfloor \le \frac{k^2 N}{k-1}. \]
The symmetric Lovász Local Lemma states that if \[ e\,p\,(D+1) \le 1, \] then $\mathbb{P}(\bigcap_P \overline{E_P})>0$, i.e. a coloring exists with no bad events. A sufficient condition is \[ e\cdot 2^{1-k}\cdot \frac{k^2 N}{k-1} \le 1, \] which is exactly $N\le \frac{(k-1)2^{k-1}}{e k^2}$. Thus such a coloring exists, implying $W(k)>N$. ∎
5) VERIFICATION / EDGE CASES
- The dependency bound in Proposition Proposition (Local Lemma bound) is intentionally crude but valid: counting progressions through each point and summing over the $k$ points of $P$ yields an upper bound on intersecting progressions.
- For $k=1,2$ the definition of $W(k)$ is trivial; Proposition Proposition (Local Lemma bound) assumes $k\ge 3$ so that the "$k$--AP" events are genuinely constrained.
- The tiny-case verification $W(3)=9$ was checked both by an explicit $[8]$ coloring and by exhaustive enumeration on $[9]$.
6) FINAL
UNRESOLVED
- Farthest point reached. I proved the standard Lovász Local Lemma lower bound $W(k)\ge c\,2^k/k$ (Proposition Proposition (Local Lemma bound)) and sanity-checked $W(3)=9$.
- Best partial lemma. Proposition Proposition (Local Lemma bound): existence of $2$--colorings of length $\asymp 2^k/k$ with no monochromatic $k$--AP.
- Smallest missing step. To prove $W(k)^{1/k}\to\infty$ one needs a qualitatively new lower bound giving $\log W(k)\gg k\log k$ (or stronger), far beyond Local Lemma/exponential constructions.
- Completion estimate. The current best general lower bounds are exponential in $k$; obtaining super--exponential growth appears to require new structural/algebraic constructions or breakthroughs in quantitative Ramsey/additive combinatorics.