Math-6237 · mathematics · Mathematics

Math-6237

Erdős Problem #1183

Status Open · erdosproblems.comLLM status Open unverified

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Statement

For every red--blue colouring of $\mathcal P([n])$, consider the largest monochromatic subfamily closed under both binary union and binary intersection. Let $f(n)$ be the minimum of this largest size over all such colourings. Define $F(n)$ in the same way with only closure under union required. Estimate both functions. In particular, are the inequalities \[F(n)\geq n^{\omega(n)}\quad\text{for some }\omega(n)\to\infty, \qquad F(n)=\exp(o(n))\] valid?

Restatement from Math-6237-A1 r1, with the source manuscript’s qualifications.

Original problem on erdosproblems.com

Statement licence: CC-BY-4.0 · Source file

Contributions 1

Math-6237-A1 · No claim recorded · LLM-generated · gpt 6 astra ultra ·

GPT 6 Astra Ultra attempt on Math-6237

Erdős Problem 1183 --- GPT 6 Astra Ultra partial attempt

FORMAL RESTATEMENT

For every red--blue colouring of $\mathcal P([n])$, consider the largest monochromatic subfamily closed under both binary union and binary intersection. Let $f(n)$ be the minimum of this largest size over all such colourings. Define $F(n)$ in the same way with only closure under union required. Estimate both functions. In particular, are the inequalities \[F(n)\geq n^{\omega(n)}\quad\text{for some }\omega(n)\to\infty, \qquad F(n)=\exp(o(n))\] valid?

CONTEXT AND SCOPE

This replaces the earlier statement-only record with an elementary mathematical attempt. The arguments below establish only their stated partial results; no novelty or full solution is claimed.

The exponential question paraphrases the page's F(n)<$1+o(1)$^n notation. Indexed comments report partial results but are not being adopted as verified proofs.

ATTACK PLAN AND WORK

Take the chain $\varnothing\subset\{1\}\subset\{1,2\}\subset\cdots\subset[n]$. At least $\lceil(n+1)/2\rceil$ of its members have the same color. Any subfamily of a chain is closed under binary union and intersection: these operations simply select the larger and smaller of their two inputs. Consequently \[\lceil(n+1)/2\rceil\le f(n)\le F(n).\tag{1}\] No closure under the empty union is being inserted into the problem.

There is a structural certificate useful for searches beyond this bound. For a nonempty finite union-closed family $\mathcal A$, the union $U$ of all its members belongs to $\mathcal A$, by repeatedly applying binary closure. If it is also intersection-closed, the intersection $I$ belongs as well, and every member lies in the interval $[I,U]$ of the Boolean lattice. Hence \[|\mathcal A|\le2^{|U\setminus I|}.\tag{2}\] The converse would be false: having same-colored endpoints does not force the intervening interval to be monochromatic or closed in a chosen subfamily.

Thus a large two-operation family needs a large interval between its extremal sets, but proving such an interval exists cannot be replaced by a count of same-colored endpoints. For union closure alone, even the common intersection need not be a family member.

VERIFICATION AND REMAINING GAP

Force monochromatic union-closed families of superpolynomial size and find matching subexponential upper constructions. The chain argument and interval certificate are linear-scale baseline tools only.

SOURCES

https://www.erdosproblems.com/1183

https://www.erdosproblems.com/forum/thread/1183

FINAL

UNRESOLVED. The full source problem remains outside the scope of the proved partial results.

COMPLETION ESTIMATE

$5\%$. This is a conservative subjective estimate toward the whole problem, not a probability that the argument is correct or a claim that a fixed fraction of the problem has been solved.

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