Conway's 99-Graph Problem
Status Open · unsolvedmath.comLLM status Open unverified
Top Open Problems openaigpt 6 astra ultra Not reported cataloguedOpenOpenStatement
Definitions and mathematical statement
Shared notation.
Unless a section says otherwise, ${\mathbb{N}}=\{1,2,\ldots\}$, ${\mathbb{Z}}$ is the ring of integers, ${\mathbb{Q}},{\mathbb{R}},{\mathbb{C}}$ are the rational, real, and complex fields, $[N]=\{1,\ldots,\lfloor N\rfloor\}$, and $\log$ is the natural logarithm. For real functions of a parameter tending to infinity, $f\ll g$ and $f=O(g)$ mean $|f|\leq Cg$ eventually for some fixed $C$; $f\gg g$ reverses this comparison; $f=o(g)$ means $f/g\to0$; $f\sim g$ means $f/g\to1$; and $f\asymp g$ means both order bounds. A subscript on $O$ or $\ll$ specifies allowed constant dependence. The expression $n^{o(1)}$ in an upper bound means growth smaller than $n^\epsilon$ for each fixed $\epsilon>0$. Local definitions govern any exception, finite-field convention, or use of the same symbol for another object. An asymptotic claim is not automatically an effective algorithm.Seek a simple graph with 99 vertices, every vertex of degree 14, every adjacent pair having exactly one common neighbour and every nonadjacent pair exactly two. These are the strongly regular parameters $(99,14,1,2)$; the graph is not specified up to any additional symmetry requirement. [S1] [S2]
Statement recorded in the supplied source.
Does there exist a strongly regular graph with parameters (99,14,1,2)? [S1]Residual task reported by the archive.
The embedded review (2026-08-17) records: Construct an srg(99,14,1,2) or prove that the remaining locally and spectrally feasible structures cannot exist. [S1]
Short English statement
Is there a ninety-nine-vertex graph with degree fourteen and exactly the prescribed common-neighbour counts for adjacent and nonadjacent pairs?Sources
- S1 ULAM.AI, UnsolvedMath, supplied
problems.json, record 1411 (GRAPH-024), statement and background. The embedded literature-review date is 2026-08-17; that is the archive’s review date, not a fresh certification. Dataset landing page: https://huggingface.co/datasets/ulamai/UnsolvedMath. - S2 P. G. Cesarz and A. J. Woldar, On the automorphism group of a putative Conway 99-graph, Algebraic Combinatorics 8 (2025), 379–398. https://doi.org/10.5802/alco.418. Bibliographic information from the supplied record.
- S3 A. Thakkar, A Forced-Structure Reduction and Verifiable Bounds for Conway's 99-Graph, arXiv:2608.11211 (2026). https://arxiv.org/abs/2608.11211. Bibliographic information from the supplied record.
Statement licence: CC-BY-4.0 · Source file
Contributions 1
gpt 6 astra ultra attempt on Math-612
Conway’s Ninety-Nine-Graph Problem
Definitions and mathematical statement
Shared notation.
Unless a section says otherwise, ${\mathbb{N}}=\{1,2,\ldots\}$, ${\mathbb{Z}}$ is the ring of integers, ${\mathbb{Q}},{\mathbb{R}},{\mathbb{C}}$ are the rational, real, and complex fields, $[N]=\{1,\ldots,\lfloor N\rfloor\}$, and $\log$ is the natural logarithm. For real functions of a parameter tending to infinity, $f\ll g$ and $f=O(g)$ mean $|f|\leq Cg$ eventually for some fixed $C$; $f\gg g$ reverses this comparison; $f=o(g)$ means $f/g\to0$; $f\sim g$ means $f/g\to1$; and $f\asymp g$ means both order bounds. A subscript on $O$ or $\ll$ specifies allowed constant dependence. The expression $n^{o(1)}$ in an upper bound means growth smaller than $n^\epsilon$ for each fixed $\epsilon>0$. Local definitions govern any exception, finite-field convention, or use of the same symbol for another object. An asymptotic claim is not automatically an effective algorithm.Seek a simple graph with 99 vertices, every vertex of degree 14, every adjacent pair having exactly one common neighbour and every nonadjacent pair exactly two. These are the strongly regular parameters $(99,14,1,2)$; the graph is not specified up to any additional symmetry requirement. [S1] [S2]
Statement recorded in the supplied source.
Does there exist a strongly regular graph with parameters $99,14,1,2$? [S1]Residual task reported by the archive.
The embedded review $2026-08-17$ records: Construct an srg$99,14,1,2$ or prove that the remaining locally and spectrally feasible structures cannot exist. [S1]
Short English statement
Is there a ninety-nine-vertex graph with degree fourteen and exactly the prescribed common-neighbour counts for adjacent and nonadjacent pairs?Research attempt
Scope and status of the route.
The graph sought has no required automorphisms. The reduction here keeps that full scope by fixing a vertex, not a symmetry group. The primary record [E1] describes essentially this forced-neighbourhood route and explicitly leaves existence unresolved. Its second version lists both Aalok Thakkar and Simone Severini; the imported bibliography above records only the former. The derivations below are self-contained and are not asserted to be a new reduction.Spectral feasibility does not exclude the parameters.
Counting length-two walks yields \[ A^2=12I-A+2J,\qquad A\mathbf1=14\mathbf1. \] The graph is connected, since any nonadjacent pair has two common neighbours. Thus the principal eigenvalue $14$ is simple. On $\mathbf1^\perp$, the eigenvalues solve $r^2+r-12=0$, so they are $3$ and $-4$. If their multiplicities are $f,g$, then \[ f+g=98,\qquad 14+3f-4g=0, \qquad (f,g)=(56,42). \] All multiplicities are nonnegative integers. Therefore the most direct spectral integrality test supplies no contradiction. It is invalid to replace the graph problem by finding a real symmetric matrix with these eigenvalues: the zero diagonal and binary entries are essential.The first neighbourhood is forced.
Fix a vertex $x$, and let $U=N(x)$, with $|U|=14$. For $u\in U$, the neighbours of $u$ within $U$ are precisely the common neighbours of $u,x$, so there is exactly one. Hence the induced graph on $U$ is a matching of seven edges. Let $W$ be the remaining $84$ vertices. Each $w\in W$ is nonadjacent to $x$ and has exactly two neighbours in $U$. Those two cannot form a matched pair: such a pair already has $x$ as its unique common neighbour.Conversely, two vertices $u,v\in U$ from different matched pairs are nonadjacent. They have $x$ as one common neighbour and no common neighbour inside $U$, because $U$ is a matching. Their second common neighbour is therefore a unique vertex of $W$. There are \[ \binom{14}{2}-7=84 \] such pairs. This establishes a bijection between $W$ and the unordered nonmatched pairs of $U$, not merely an upper bound on their number. Each $u\in U$ belongs to twelve pair labels, and each $w\in W$ has its remaining twelve neighbours within $W$.
Explicit residual integer equations.
Let $M$ be the $14$ by $14$ adjacency matrix of the matching. Let $B$ be the $14$ by $84$ incidence matrix of the nonmatched pairs: each column has two ones, and each row has twelve. All entries of $B$ are fixed after labeling the seven matched pairs. Its Gram matrix is \[ BB^T=11I+J-M. \] Indeed the diagonal is twelve; a matched pair of rows has intersection zero; all other pairs have intersection one. The full adjacency matrix must take the form \[ A=\begin{pmatrix} 0&\mathbf1^T&0\\ \mathbf1&M&B\\ 0&B^T&C \end{pmatrix}, \] where $C$ is symmetric, binary, has zero diagonal, and has row sum twelve. The remaining blocks of $A^2=12I-A+2J$ give \[ BC=2J-B-MB, \qquad C^2+B^TB=12I-C+2J. \] Here the all-ones matrices have the sizes dictated by the equations. Conversely any such $C$ produces the required full matrix: the root blocks follow from the column sums of $B$; the $U,U$ block follows from $M^2=I$ and the displayed formula for $BB^T$; the two remaining blocks are exactly these equations. Thus this is an equivalent finite feasibility problem, with no discarded asymmetric solutions.The first residual equation has a direct interpretation. For each outside vertex and each member of $U$, it fixes how many neighbours of that outside vertex carry the member in their pair labels. The quadratic equation then enforces the common-neighbour counts inside $W$. Satisfying only the row sums and the first equation is not enough; those conditions do not determine $C^2$.
Additional counts and a model that checks the reduction.
There would be $99\cdot14/2=693$ edges. Each edge lies in a unique triangle, giving $231$ triangles. There are $\binom{99}{2}-693=4158$ nonedges. Each has two common neighbours, so it is a diagonal of a four-cycle. The common neighbours cannot be adjacent, since then that edge would have two common neighbours. Every such cycle is induced and is counted by its two diagonals, giving $2079$ induced four-cycles. These integral counts agree; they do not force incompatible incidence.For an actual smaller instance, take the nine squares of a $3$ by $3$ board and join squares in the same row or column. Adjacent squares have one common neighbour and nonadjacent squares have two. At a fixed square its four neighbours induce two matched edges, and its four outside vertices correspond exactly to the four nonmatched pairs. The script checks every common-neighbour count and these four labels. This validates the combinatorial reduction on a genuine example, not the existence of its ninety-nine-vertex counterpart.
Verification record and remaining gap.
The exact small checks are inchecks_graphs.py and results_graphs.json under _Local/Erdos_problems/UnsolvedMath/attempt_audit_2026_10_01/number_theory/. No exhaustive feasibility search on the $84$ by $84$ unknown matrix was run. In particular a partial-score adjacency matrix, a failed circulant search, or a restriction on possible automorphisms would not settle the unrestricted equations. A binary solution $C$ or a complete infeasibility certificate is the precise missing output. Outcome: UNRESOLVED.Sources
- S1 ULAM.AI, UnsolvedMath, supplied
problems.json, record 1411 (GRAPH-024), statement and background. The embedded literature-review date is 2026-08-17; that is the archive’s review date, not a fresh certification. Dataset landing page: https://huggingface.co/datasets/ulamai/UnsolvedMath. - S2 P. G. Cesarz and A. J. Woldar, On the automorphism group of a putative Conway 99-graph, Algebraic Combinatorics 8 $2025$, 379–398. https://doi.org/10.5802/alco.418. Bibliographic information from the supplied record.
- S3 A. Thakkar, A Forced-Structure Reduction and Verifiable Bounds for Conway's 99-Graph, arXiv:2608.11211 $2026$. https://arxiv.org/abs/2608.11211. Bibliographic information from the supplied record.
- E1 Aalok Thakkar and Simone Severini, A Forced-Structure Reduction and Verifiable Bounds for Conway's 99-Graph, arXiv:2608.11211v2, revised 18 September 2026. https://arxiv.org/abs/2608.11211v2. Primary abstract and version metadata inspected 1 October 2026. The reported search scores are partial constructions, not existence certificates.