Math-1690 · mathematics · Probability

Math-1690

Convergence of synchronous reflected-Brownian couplings

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Statement

Definitions and mathematical statement

Let $D\subseteq\mathbb R^2$ be connected and open with smooth boundary, and let $\mathbf n$ denote its inward unit normal. For distinct starting points $x,y\in\overline D$, a synchronous reflected-Brownian coupling is the pair solving \[ X_t=x+B_t+\int_0^t\mathbf n(X_s)\,dL_s^X, \qquad Y_t=y+B_t+\int_0^t\mathbf n(Y_s)\,dL_s^Y, \] with the same standard planar Brownian driver $B$. The paths stay in $\overline D$. Each $L$ is continuous and nondecreasing, starts at zero, and increases only when its corresponding path is on $\partial D$; these are the boundary pushing terms in the Skorokhod reflection equations.

First, does there exist a bounded such domain and a pair of distinct initial points for which \[ \mathbb P\left(\limsup_{t\to\infty}|X_t-Y_t|>0\right)>0? \] Second, does this positive-probability assertion hold for distinct initial points when $D$ is the exterior of a nondegenerate closed Euclidean disk?

No independence between $X$ and $Y$ is intended: their dependence is fixed by the common driver. The event means that the distance fails to converge to zero and is positive along arbitrarily late times by some sample-dependent amount. It is weaker than asking the two paths to remain uniformly separated at all times. The bounded-domain question allows holes, while the exterior-disk question concerns an unbounded domain with one compact boundary component.

Short English statement

Can synchronously driven reflected Brownian motions fail to approach each other in a bounded planar domain or outside a disk?

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