Math-1533 · mathematics · Graph theory

Math-1533

Conjecture 3.20 — Nesterenko

Status Partially solved · unsolvedmath.comLLM status Open unverified

Top Open Problems Not reported cataloguedPartially solvedOpen

Statement

Definitions and mathematical statement

Let $\tau\in\mathbb C$ have positive imaginary part, and suppose $\tau$ is not algebraic of degree two over $\mathbb Q$. Set $q=e^{2\pi i\tau}$, so $0<|q|<1$. Define Ramanujan's series by \[ \begin{aligned} P(q)&=1-24\sum_{n\ge1}\frac{nq^n}{1-q^n},\\ Q(q)&=1+240\sum_{n\ge1}\frac{n^3q^n}{1-q^n},\\ R(q)&=1-504\sum_{n\ge1}\frac{n^5q^n}{1-q^n}. \end{aligned} \] All three series converge absolutely in the open unit disc. These definitions fix the normalization; in Eisenstein-series notation they are $E_2(\tau),E_4(\tau),E_6(\tau)$.

Nesterenko's conjecture asks whether at least four of the five numbers $\tau,q,P(q),Q(q),R(q)$ are algebraically independent over $\mathbb Q$. Equivalently, the field they generate should have transcendence degree at least four. Algebraic independence means that no nonzero rational polynomial vanishes on the chosen four entries; the choice of four may depend on $\tau$.

The hypothesis permits both transcendental $\tau$ and algebraic $\tau$ of degree greater than two. An upper-half-plane point cannot have degree one over $\mathbb Q$. The excluded quadratic points are precisely the imaginary quadratic algebraic parameters in this domain.

The statement concerns the simultaneous arithmetic nature of the parameter, its exponential, and three specific analytic values. It is not an assertion of algebraic independence of the series as formal functions, nor does separate transcendence of their numerical values suffice for the required lower bound.

Short English statement

Away from imaginary quadratic parameters, do the parameter, its exponential, and Ramanujan’s three series have joint transcendence degree at least four?

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