Math-3393 · mathematics · Topology

Math-3393

Atomicity of the poset of completary multifuncoids

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Statement

Definitions and mathematical statement

Shared notation.
$\mathbb N=\{1,2,\ldots\}$, and $\mathbb Z,\mathbb Q,\mathbb R,\mathbb C$ denote the integers, rationals, reals and complex numbers. Any other conventions are specified locally.

For an index set $I$ and join-semilattices $L_i$ with bottom $0_i$, their product is ordered coordinatewise. Call $F\subseteq\prod_{i\in I}L_i$ completary when, for every $u,v$ in that product, \[ (u_i\vee v_i)_{i\in I}\in F \quad\Longleftrightarrow\quad \exists c:I\to\{0,1\}:\ (w_i)_{i\in I}\in F, \quad w_i=\begin{cases}u_i&c(i)=0,\\v_i&c(i)=1,\end{cases} \] and no tuple having a bottom coordinate belongs to $F$. This is the source's definition of a completary multifuncoid.

Order the specified collections of multifuncoids by set inclusion. The bottom is the empty multifuncoid. An atom is a nonempty element $A$ with no nonempty element strictly below it. Atomic means every nonempty element has an atom below it. Atomistic means every element is the least upper bound, in this poset, of all atoms below it; this specifies the join as a poset join rather than an unverified raw set union.

Statement recorded in the supplied source.
For every set $X$ and index set $I$, is the inclusion poset of completary multifuncoids $F\subseteq\mathcal P(X)^I$ both atomic and atomistic? Here each coordinate lattice is $(\mathcal P(X),\subseteq,\cup,\varnothing)$. Both assertions and all finite or infinite index sets are included. [S2]

Short English statement

Do all nonempty completary multifuncoids on powersets contain an atom, and is each determined as the join of its atoms?

Sources

Catalogue entry

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